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3 years ago

Which measure of center would you use to compare the symmetric populations represented by the box plots?

Mathematics

2 answers:

trapecia [35]3 years ago

4 0

Answer:

Step-by-step explanation:

1. mean 2. mean absolute deviation

Ilya [14]3 years ago

3 0

Answer:

1. mean 2. mean absolute deviation

Step-by-step explanation:

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The radioactive isotope radium has a half-life of 1,600 years. The mass of a 100-gram sample of radium will be______ grams after

Olenka [21]

To solve this we are going to use the half life equation $N(t)=N_{0} e^{( \frac{-0.693t}{t _{1/2} }) }$
Where:
$N_{0}$ is the initial sample
$t$ is the time in years
$t_{1/2}$ is the half life of the substance
$N(t)$ is the remainder quantity after $t$ years

From the problem we know that:
$N_{0} =100$
$t=200$
$t_{1/2} =1600$

Lets replace those values in our equation to find $N(t)$ :
$N(200) =100e^{( \frac{(-0.693)(200)}{1600}) }$
$N(200)=100e^{( \frac{-138.6}{1600} )}$
$N(200)=100e^{-0.086625}$
$N(200)=91.7$

We can conclude that after 1600 years of radioactive decay, the mass of the 100-gram sample will be 91.7 grams.

8 0

3 years ago

A _______ divides an angle into two congruent angles

aliina [53]

Angle bisector would be the answer

6 0

3 years ago

A sales team estimates that the number of new phones they will sell is a function of the price that they set. They estimate that

USPshnik [31]

Answer:

$204

Step-by-step explanation:

The question is at what price x will the company maximize revenue.

The revenue function is:

$R(x) = 4,080x-10x^2$

The price for which the derivate of the revenue function is zero is the price the maximizes revenue:

$R(x) = 4,080x-10x^2\\\frac{dR(x)}{dx}=0=4,080-20x\\x=\frac{4,080}{20}\\ x=\$204$

The company will maximize its revenue when the price is $204.

7 0

3 years ago

#54 Simplify and write the answers using positive exponents only.

kramer

Gg easy

remember
(x^m)/(x^n)=x^(m-n)
and
(x^m)^n=x^(mn)
and
(xyz)^m=(x^m)(y^m)(z^m)
and
(m/n)^a=(m^a)/(n^a)
and
x^-n=1/(x^n)

so
$( \frac{6mn^{-2}}{3m^{-1}n^2} )^{-3}$ =
$( \frac{6}{3} )^{-3}( \frac{m}{m^{-1}} )^{-3}( \frac{n^{-2}}{n^2} )^{-3}$ =
$(2^{-3})((m^2)^{-3})((n^{-4})^{-3})$ =
$( \frac{1}{2^3})(m^{-6})(n^{12})$ =
$( \frac{1}{8} )( \frac{1}{m^6})(n^{12})$ =
$\frac{n^{12}}{8m^6}$

8 0

3 years ago

HELP ME DUE IN 2 HRS!

almond37 [142]

Answer:

190.67 ft/sec

Step-by-step explanation:

130 mi/hr x 5280 ft/mi x 1/60 hr/min x 1/60 min/sec = 190.67 ft/sec

It makes more sense if you write these as fractions and cancel units.

5 0

3 years ago