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2 years ago

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Twice the sum of a number and 11 is 34. What is the number?

2 answers:

cupoosta [38]2 years ago

4 0

28

34 ay 17. So 11 + 17 = 28

cricket20 [7]2 years ago

4 0

Answer:

Twice the sum of 11.5 and 11 is 34.

Step-by-step explanation:

Twice the sum of a number and 11 is 34.

This implies the equation:

2x+11=34 -> Solve for X.

34-11=23.

23/2=11.5

X=11.5

Could also use Desmos calculator for this, in which it would look like:

<em><u>(Brainliest?)</u></em> ^^

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Dada la ecuacion 25x2 + 4y2 = 100, determina las coordenadas de los vertices, focos, las longitudes de los respectivos ejes mayo

Likurg_2 [28]

Answer:

The given equation is

$25x^{2} +4y^{2}=100$

Which represents an elipse.

To find its elements, we need to divide the equation by 100

$\frac{25x^{2} +4y^{2} }{100} =\frac{100}{100} \\\frac{x^{2} }{4} +\frac{y^{2} }{25} =1$

Where $a^{2} =25$ and $b^{2}=4$ . Remember that the greatest denominator is $a$ , and the least is $b$ . So, we extract the square root on each equation.

$a=5$ and $b=2$ .

In a elipse, we have a major axis and a minor axis. In this case, the major axis is vertical and the minor axis is horizontal, that means this is a vertical elipse.

The length of the major axis is $2a=2(5)=10$ .

The length of the minor axis is $2b=2(2)=4$ .

The vertices are $(0,5);(0,-5)$ and $(2,0);(-2,0)$ .

Now, the main parameters of an elipse are related by

$a^{2}=b^{2} +c^{2}$ , which we are gonna use to find $c$ , the parameter of the focus.

$c=\sqrt{a^{2}-b^{2} }=\sqrt{25-4}=\sqrt{21}$

So, the coordinates of each focus are $(0,\sqrt{21})$ and $(0,-\sqrt{21})$

The eccentricity of a elipse is defined

$e=\frac{c}{a}=\frac{\sqrt{21} }{5} \approx 0.92$

The latus rectum is defined

$L=\frac{2b^{2} }{a}=\frac{2(4)}{5} =\frac{8}{5} \approx 1.6$

Finally, the graph of the elipse is attached.

7 0

3 years ago

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Cloud [144]

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3 0

3 years ago

Hello What is 5X+2x-3x

Sedaia [141]

I think 5X+1x. Sorry if it's wrong.

5 0

3 years ago

Read 2 more answers

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mote1985 [20]

Divide 298 by 4 then you should get your answer

5 0

3 years ago

Read 2 more answers

Ms. Higdon is planning her wedding. One venue charges

Diano4ka-milaya [45]

Answer:

80 people would need to attend for the venues to cost the same amount.

Step-by-step explanation:

Let the total number of people who attend the wedding = m

The venue charges of venue 1 = $10,000

The per person charge of Venue 1 = $25 per person

So, the charge for m people = m x ($25) = 25 m

So ,The total charge of Venue 1 = Venue Charge + People Cost

= $10, 000 + 25 m

Now, The per person charge of Venue 2 = $150 per person

So, the charge for m people = m x ($150) = 150 m

So ,The total charge of Venue 2 = 150 m

According to question:

For m people both charges are equal ⇒ $10, 000 + 25 m = 150 m

or, 10,000 = 150 m - 25 m

⇒ 125 m = 10,000

⇒ m = 10,000 / 125 = 80

or, m = 80

Hence, 80 people would need to attend for the venues to cost the same amount.

3 0

3 years ago