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posledela
3 years ago
9

A) -3 · x = -21 b) -7x + 16 = 2x - 20

Mathematics
2 answers:
scoundrel [369]3 years ago
7 0

Answer:7

Step-by-step explanation:

A) x= -21/-3

= 7 answer

Angelina_Jolie [31]3 years ago
4 0

Answer:

Step-by-step explanation:

a) -3x = -21

Divide both sides by (-3)

-3x/-3 = -21/-3

x = 7

b)  -7x + 16 = 2x - 20

Subtract 16 from both sides

-7x + 16 -16 = 2x - 20 -16

-7x = 2x - 36

Subtract 2x from both sides

-7x -2x = 2x - 36 - 2x

-9x = -36

Divide both sides by (-9)

-9x/-9 = -36/-9

x = 4

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Calculate the pH of a buffer solution made by mixing 300 mL of 0.2 M acetic acid, CH3COOH, and 200 mL of 0.3 M of its salt sodiu
Lesechka [4]

Answer:

Approximately 4.75.

Step-by-step explanation:

Remark: this approach make use of the fact that in the original solution, the concentration of  \rm CH_3COOH and \rm CH_3COO^{-} are equal.

{\rm CH_3COOH} \rightleftharpoons {\rm CH_3COO^{-}} + {\rm H^{+}}

Since \rm CH_3COONa is a salt soluble in water. Once in water, it would readily ionize to give \rm CH_3COO^{-} and \rm Na^{+} ions.

Assume that the \rm CH_3COOH and \rm CH_3COO^{-} ions in this solution did not disintegrate at all. The solution would contain:

0.3\; \rm L \times 0.2\; \rm mol \cdot L^{-1} = 0.06\; \rm mol of \rm CH_3COOH, and

0.06\; \rm mol of \rm CH_3COO^{-} from 0.2\; \rm L \times 0.3\; \rm mol \cdot L^{-1} = 0.06\; \rm mol of \rm CH_3COONa.

Accordingly, the concentration of \rm CH_3COOH and \rm CH_3COO^{-} would be:

\begin{aligned} & c({\rm CH_3COOH}) \\ &= \frac{n({\rm CH_3COOH})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}.

\begin{aligned} & c({\rm CH_3COO^{-}}) \\ &= \frac{n({\rm CH_3COO^{-}})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}.

In other words, in this buffer solution, the initial concentration of the weak acid \rm CH_3COOH is the same as that of its conjugate base, \rm CH_3COO^{-}.

Hence, once in equilibrium, the \rm pH of this buffer solution would be the same as the {\rm pK}_{a} of \rm CH_3COOH.

Calculate the {\rm pK}_{a} of \rm CH_3COOH from its {\rm K}_{a}:

\begin{aligned} & {\rm pH}(\text{solution}) \\ &= {\rm pK}_{a} \\ &= -\log_{10}({\rm K}_{a}) \\ &= -\log_{10} (1.76 \times 10^{-5}) \\ &\approx 4.75\end{aligned}.

7 0
3 years ago
the length of each side of the square increases by 2.5 inches to form a new square with a perimeter of 70 inches. The length of
lozanna [386]
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2.5*4=10

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3 years ago
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Answer:

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Step-by-step explanation:

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m < 1 = 80 degrees

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Can someone please help me with these two questions? I would be really grateful...
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Answer:

1. County B

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