Because of the symmetry, we can just go from x=0 to x=2 to find the area between
<span>y = x^2 and y = 4 </span>
<span>that area = ∫4-x^2 dx from 0 to 2 </span>
<span>= [4x - (1/3)x^3] from 0 to 2 </span>
<span>= 8 - 8/3 - 0 </span>
<span>= 16/3 </span>
<span>so when y = b </span>
<span>x= √b </span>
<span>and we have the area as </span>
<span>∫(b - x^2) dx from 0 to √b </span>
<span>= [b x - (1/3)x^3] from 0 to √b </span>
<span>= b√b - (1/3)b√b - 0 </span>
<span>(2/3)b√b = 8/3 </span>
<span>b√b =4 </span>
<span>square both sides </span>
<span>b^3 = 16 </span>
<span>b = 16^(1/3) = 2 cuberoot(2) </span>
<span>or appr 2.52</span>
Answer:
complementary angles
Step-by-step explanation:
it's a 90 degree angle added together (notice the square in the corner?) hope this helps!
Answer:
a) (-9,3)
Step-by-step explanation:
x + 2y = -3
- (x - y = -12)
<u />
x + 2y = -3
<u>- x + y = 12</u>
3y = 9
y = 3
x - y = -12
x- 3 = -12
x= - 9
(-9, 3)
Three solutions:
x=0
x=7/2
x=-6
