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3 years ago

Factor the expression by grouping (show work/steps) -4x^3 - 12x^2 + 8x + 24

1 answer:

lisabon 2012 [21]3 years ago

5 0

Factor out -4
-4(x^3+3x^2-2x-6
Factor out x^2
-4(x^2(x+3)-2x-6)
Factor out -2
-4(x^2(x+3)-2(x+3))
Factor out x+3
-4(x+3)(x^2-2)

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Heidi and Andrew designed two raised flowerbeds for their garden. Heidi’s flower bed was 5 feet long by 3 feet wide, and Andrew’

Alona [7]

Answer:

90 ft³

Step-by-step explanation:

Volume is calculated as length × width × height.

Heidi: 5×3×2 = 30 ft³

Andres: 5×6×2 = 60 ft³

Total: 30 + 60 = 90 ft³

3 0

2 years ago

Solve. Round to the nearest tenth. 6 2-12 19 2x-2 HELP ASAP!!

Strike441 [17]

Answer:

$\displaystyle x = \frac{216}{7}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Step-by-step explanation:

Step 1: Define

$\displaystyle \frac{6}{19} = \frac{x - 12}{2x - 2}$

Step 2: Solve for x

Cross-multiply: $\displaystyle 6(2x - 2) = 19(x - 12)$
Distribute: $\displaystyle 12x - 12 = 19x - 228$
Isolate x terms: $\displaystyle -12 = 7x - 228$
Isolate x term: $\displaystyle 216 = 7x$
Isolate x: $\displaystyle \frac{216}{7} = x$
Rewrite: $\displaystyle x = \frac{216}{7}$

6 0

2 years ago

Read 2 more answers

3. Kirk bought a bag of candy and took 10

tamaranim1 [39]

70, Multiply 5 pieces by 12 friends and you get 60, then add the 10 pieces he originally took out, and you get 70

8 0

3 years ago

The current year’s depreciation expense using the straight-line method and assuming only one depreciable property, is P20,000. W

denpristay [2]

Answer:

Machine's useful number of years = 9 years

Step-by-step explanation:

Using the straight line method, depreciation is calculated as the difference between the cost of the equipment minus the salvage value, all divided by the number of useful years.

Yearly Depreciation

= (Cost - Salvage value) ÷ (Number of useful years)

Yearly depreciation = P20,000

Cost = P200,000

Salvage Value = P20,000

Number of useful years = n

20000 = (200000 - 20000) ÷ n

20000 = (180000/n)

n = (180000/20000) = 9 years

Hope this Helps!!!

8 0

2 years ago

Suppose the cost of electricity is $0.03 for each kilowatt-hour. Carlos's house runs on 11.14 kilowatt-hours a day. Find the cos

irga5000 [103]

Answer: I think the answer is $33.42

Explanation: If it’s $0.03 for every hour and there is only 11.14 hours used a day just multiply 11.14 by .03 and you get .3342 then you move the decimal over 2 spaces to get 33.42

8 0

2 years ago