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Mama L [17]
3 years ago
13

Prime Factorization

Mathematics
1 answer:
maks197457 [2]3 years ago
8 0
What's your question
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If you were to be driving in a car at a high amount of speed and shot a gun out the window forward (towards the windshield forwa
marin [14]

Answer:

If you shoot the bullet off the back of the car , the bullet will still be moving away from you and the gun at 1,000 mph, but now the speed of the train will subtract from the speed of the bullet. Relative to the ground, the bullet will not be moving at all, and it will drop straight to the ground.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
QTR is a right triangle TQR is a right triangle QS is an altitude which statements are true
mars1129 [50]

Answer:

A and C

Step-by-step explanation:

for A

QT/RT=ST/QT=QS/QR  

There are two QT's in this

so

(QT)^2 = RT * ST

FOR B

there is no RT twice

for C

QR/RT RS/QR

There is a QR twice

so QR^2=RT*RS

FOR D there is no RT twice  

(if you have the other answers for this quiz plz give them to me lol)

4 0
3 years ago
The cost to the store for basketball shoes is $75. The selling price is $112.50. What is the percent markup?
kati45 [8]

Answer:

15%

If you get 7.5 from 75 by moving over 1 decimal place then divide 112.50 by 7.5 you get 15 percent as your answer

7 0
3 years ago
4x^4+35x^2-9=0 solve by factoring
Elden [556K]
O si it told me that the solution was -1/2,x2 and it equals =1/2 hope it helps
6 0
3 years ago
Solve the following system of equations.<br> 2x+y=3<br> I= 2y - 1<br> x=<br> y=
marin [14]

<em>Note: I am assuming your second equation is:</em>

<em>x = 2y - 1</em>

<em></em>

Answer:

The solution to the system of equations is:

  • x = 1
  • y = 1

Step-by-step explanation:

Given the system of equations

2x+y=3

x = 2y - 1

solving the system of equations using the elimination method

\begin{bmatrix}2x+y=3\\ x=2y-1\end{bmatrix}

Arrange equation variables for elimination

\begin{bmatrix}2x+y=3\\ x-2y=-1\end{bmatrix}

Multiply x-2y=-1 by2:     2x-4y=-2

\begin{bmatrix}2x+y=3\\ 2x-4y=-2\end{bmatrix}

subtracting the equations

2x-4y=-2

-

\underline{2x+y=3}

-5y=-5

now solve -5y = -5 for y

-5y=-5

Divide both sides by -5

\frac{-5y}{-5}=\frac{-5}{-5}

Simplify

y=1

For 2x+y=3 plug in y=1

2x+1=3

subtract 1 from both sides

2x+1-1=3-1

Simplify

2x=2

Divide both sides by 2

\frac{2x}{2}=\frac{2}{2}

Simplify

x=1

Therefore, the solution to the system of equations is:

  • x = 1
  • y = 1
8 0
3 years ago
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