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3 years ago

What is the area of a rectangle with a dimension of 5 cm and 3/4 cm? PLEASE EXPLAIN AND I WILL MARK YOU BRAINLIEST.

Mathematics

2 answers:

wlad13 [49]3 years ago

8 0

Answer:

3.75 cm^2

Step-by-step explanation:

Area of a rectangle = Length x Width.

If we are given that the length is 5 cm and width is 3/4 cm ( you could convert this to a 0.75 if you want to as well ) we can plug this in:

Area = 5 cm x 3/4 cm

Solving for Area we get:

Area = 3.75 cm^2.

jonny [76]3 years ago

5 0

Answer:

$\boxed{ \bold{ \huge{ \bold{ \boxed{ \sf{3.75 \: {cm}^{2} }}}}}}$

Step-by-step explanation:

Length ( l ) = 5 cm

Width ( w ) = 3/4 cm

To find : Area of a rectangle

Finding the area of a rectangle having length of 5 cm and width of 3/4 cm

$\boxed{ \sf{area \: of \: rectangle = \: l \times w}}$

plug the values

$\dashrightarrow{ \sf{5 \times \frac{3}{4} }}$

To multiply one fraction by another, multiply the numerators for the numerator, and multiply the denominator for its denominator.

$\dashrightarrow{ \sf{ \frac{5 \times 3}{4} }}$

$\dashrightarrow{ \sf{ \frac{15}{4} }}$

Divide 15 by 4

$\dashrightarrow{ \sf{3.75 \: {cm}^{2} }}$

Hope I helped!

Best regards! :D

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What is the equation of the circle with center (1, -1) that passes through the point (5, 7)?

Inessa [10]

Answer:

Equation of the circle =

80 = ( x - 1)^2 + (y + 1)^2

Step-by-step explanation:

Center = (1 , -1)

Point = ( 5 , 7)

Eqn of a circle is

r^2 = (x - h)^2 + (y - k)^2

We are not given the radius of the circle, fortunately we are provided the information that the circle contains a point ( 5, 7), so we use the above information to find r

Using the center (1, -1)

h - 1

k - -1

r^2 = (x - 1)^2 + ( y - -1)^2

r^2 = (x - 1)^2 + (y + 1)^2

With the point ( 5,7)

x = 5

y = 7

r^2 = ( 5 - 1)^2 + ( 7 + 1)^2

= 4^2 + 8^2

= 16 + 64

= 80

r^2 = 80

r = square root of 80

r = 8.94

The r = 8.94 , which means the equation of the circle is

80 = (x - 1)^2 + ( y + 1)^2

5 0

3 years ago

Can someone pls help me :)

Diano4ka-milaya [45]

Answer: c

Step-by-step explanation:

If the population triples every three hours, you would multiply three by the number of one hour to the power of three, making three hours. This function would triple it every three hours.

4 0

3 years ago

What is the solution for the equation 14.8 equals n -0.3

vodomira [7]

Hello there!

$14.8=n-0.3$

Answer:

$\boxed{n=15.1=15.0}$

You can also round up to the nearest tenths is 15.1 to 15.0 and its going to be stay.

Step-by-step explanation:

First you had to switch sides of equation form.

$n-0.3=14.8$

Then you add by 0.3 from both sides of equation form.

$n-0.3+0.3=14.8+0.3$

And finally, simplify by equation. You can also cross out by -0.3+0.3 and it gave us equal to zero. Then you add 14.8+0.3 and it equal to 15.1. You had to used their variable and its should be the right answer.

$n=15.1$

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

6 0

2 years ago

A chemical balance needs to weigh 237g using weights of 50g, 20g, 10g and 1g. How many of each weight is needed?

Delicious77 [7]

The required number of weights used in chemical balance to weigh 237g is 4,1,1,7 respectively.

What is mathematical expression?

A mathematical expression expression in mathematical is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Here, it is given that :

A chemical balance needs to weigh 237g using weights of 50g, 20g, 10g and 1g.

Now, let us find the number of weights for each weight type :

For 50g weight the maximum number of weights needed will be 4 that is :

50g x 4 = 200g

Now, for 20g weight the maximum number of weights needed will be 1 that is :

20g x 1 = 20g

Now, for 10g weight the maximum number of weights needed will be 1 that is :

10g x 1 = 10g

Now, for 1g weight the maximum number of weights needed will be 7 that is :

1g x 7 = 7g

Adding all the weights we get :

200g + 20g + 10g + 7g = 237g;

which is the required weight and the number of weights used is 4,1,1,7 respectively.