All categories

3 years ago

What value of x is in the solution set of 2x - 3> 11 - 5x? -3 0 02 4

Mathematics

1 answer:

Oliga [24]3 years ago

8 0

The value of x is 2. hope it helps!

You might be interested in

The area of a rectangle is expressed as (14r + 21) square feet. If the width of the

lilavasa [31]

Answer:

L = 2r + 3

Step-by-step explanation:

Given parameters:

Area of rectangle = 14r + 21

Width of the rectangle = 7ft

Unknown:

Length of the rectangle = ?

Solution:

If the length of the rectangle is designated as L;

Area of a rectangle = Length x width

Now insert the parameters:

14r + 21 = L x 7

L = $\frac{14r + 21}{7}$

L = 2r + 3

8 0

3 years ago

The value of m is a distance of 3 1/2 units from -2 on a number line which number if any could be a value of M

Verizon [17]

Answer:

100

Step-by-step explanation:

8 0

2 years ago

Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.

Aleks [24]

Answer:

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

Step-by-step explanation:

The actual Series is::

$\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$

The method we are going to use is comparison method:

According to comparison method, we have:

$\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n$

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

$=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}$

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}$

Now:

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}$

So a_n is finite, so it converges.

Similarly b_n converges according to p-test.

P-test:

General form:

$\sum_{n=1}^{inf}\frac{1}{n^p}$

if p>1 then series converges. In oue case we have:

$\sum_{n=1}^{inf}b_n=\frac{1}{n^4}$

p=4 >1, so b_n also converges.

According to comparison test if both series converges, the final series also converges.

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

5 0

3 years ago

alecu a imprumutat de la un prieten romanul lui james verne ,,Ocolul Pamintului" in 80 de zile. Daca ar citi zilnic 14 pagini, a

ycow [4]

Salut!
Alecu ar citi in 12 zile 14 x 12 = 168 de pagini (atatea pagini are cartea);
O saptamana are 7 zile, asa ca 168 ÷ 7 = 24 de pagini trebuie sa citeasca zilnic Alecu ca sa inapoieze cartea la sfarsitul celor 7 zile;
Succes!

8 0

3 years ago

Compare and Contrast: Two equations are listed below. Solve each equation and compare the solutions. Choose the statement that i

Alex Ar [27]

No equations are listed

4 0

3 years ago