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3 years ago

What is the absolute value of -1+3i

Mathematics

1 answer:

Ierofanga [76]3 years ago

4 0

Answer:

bsdjsds

Step-by-step explanation:

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Describe in words the region of R3 reperesented by the equations or inequalities x2+y2+z2≤3

Vaselesa [24]

Answer:

The region represented by the equation is a full sphere of radius √3 centered in the origin of coordinates.

Step-by-step explanation:

In a plane xy, the equation that represents a circle with center in the origin, of radius r is

$x^2+y^2=r^2$

in R³, or a space xyz, we can represent a sphere with its center in the origin, and of radius r, with the equation

$x^2+y^2+z^2=r^2$

So, in this problem we have that

$3=r^2$

which means that the sphere has a radius of √3.

Finally, our equation is an inequality, and the sphere is equal to, and less than, the calculated radius.

Therefore, the sphere is "full" from the surface to its center.

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3 years ago

PLEASE ANSWER ASAP FOR BRAINLEST, REALLY EASY QUESTION!!!!!!!!!!!!!!!!!!!!!!!

Marina86 [1]

The answer is C

survey an equal number of boys and girls

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3 years ago

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yaroslaw [1]

Answer:

Step-by-step explanation:

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3 years ago

which equation shows the point-slope form of the line that passes through (3, 2) and has a slope of 1/3 ?

denis23 [38]

Answer:

$y-2=\frac{1}{3}(x-3)$

Step-by-step explanation:

we know that

The equation of the line into point slope-form is equal to

$y-y1=m(x-x1)$

in this problem we have

$m=\frac{1}{3}$

$(x1,y1)=(3,2)$

substitute the values in the formula

$y-2=\frac{1}{3}(x-3)$

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3 years ago

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What is the image of (-9,0) after a reflection over the line y=x

SpyIntel [72]

Answer:

(0,-9)

Step-by-step explanation:

The image of a point $(x,y)$ over a line $y=x$ is given by the co-ordinate rule:

$(x,y)$ → $(y,x)$

So, when we reflect a point over the line $y=x$ , the x co-ordinate and y co-ordinate change their places.

Here, $(x,y)$ is $(-9,0)$ . So, from the above rule, after reflection over the line $y=x$ , the image has the following co-ordinates:

$(0,-9)$

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3 years ago