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3 years ago

Evaluate the following.

Mathematics

1 answer:

kondaur [170]3 years ago

7 0

4, then 13. Since the 4 is positive it doesn’t need to change, and 13 is negative therefore it will be positive

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It is in the attachment.

Setler79 [48]

Answer:

you would have to pay $43.20

Step-by-step explanation:

15+32.50=47.50

47.50x.08=3.80

47-3.80=43.20

3 0

3 years ago

Simplify the imaginary number sqr -75

m_a_m_a [10]

Answer:

5i $\sqrt{3}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

and $\sqrt{-1}$ = i

Given

$\sqrt{-75}$

= $\sqrt{25(3)(-1)}$

= $\sqrt{25}$ × $\sqrt{3}$ × $\sqrt{-1}$

= 5 × $\sqrt{3}$ × i

= 5i $\sqrt{3}$

3 0

3 years ago

Xavier ran four miles on his first day of training. The next day he ran eight ninths that distance. How far did he run on the se

serg [7]

Well, it's the product of 8/9 and the 4 miles. The result is 32/9 miles, that is, 3,55 miles.

7 0

3 years ago

What is the value of x and y?

aksik [14]

Answer:

Any thing u want

Step-by-step explanation:

The value of y is 25 means, in this equation, no matter what value you choose for x, y will always equal 25. So x can be anything you want.

7 0

3 years ago

HELP THIS IS HARD SOMEONE pls

IrinaK [193]

Answer:

3rd option

Step-by-step explanation:

Since the centre of dilatation is at the origin then multiply the coordinates by $\frac{1}{3}$

K (- 3, 9 ) → K' (- 3( $\frac{1}{3}$ ), 9( $\frac{1}{3}$ ) ) → K' (- 1, 3 )

L (- 9, 0 ) → L' (- 9( $\frac{1}{3}$ ), 0 ( $\frac{1}{3}$ ) ) → L' (- 3, 0 )

M (2, - 8 ) → M' (2 ( $\frac{1}{3}$ ), - 8 ( $\frac{1}{3}$ ) ) → M' ( $\frac{2}{3}$ , - $\frac{8}{3}$ )

N (6, 4 ) → N' (6 ( $\frac{1}{3}$ ) , 4 ( $\frac{1}{3}$ ) ) → N' ( 2, $\frac{4}{3}$ )

7 0

3 years ago