Given:
The graph of a line.
To find:
The point-slope form of the given line.
Solution:
From the given graph it is clear that the line passes through the point (1,5) and (0,-1). So, the slope of the line is:
The slope of the line is 6 and it passes through the point (1,5). So, the point slope form of the line is:
Therefore, the point-slope form is , slope is 6 and the point is (1,5).
We can break down the number 6647 into:
6647=6000+600+40+7
The first 6 in the number is in the thousands place (6,000), and the second 6 is in the hundreds place (600).
The first 6 is 10 times greater than the second one.
Answer:
Find the answers below
Step-by-step explanation:
Using m<X as the reference angle
Opposite YZ = 7
Adjacent XY = 10
Hypotenuse XZ = √149
Using the SOH CAH TOA identity
sinX = opp/hyp
sinX =YZ/XZ
sinX = 7/√149
For cos X
cos X = adj/hyp
cos X =10/√149
Using m<Z as reference angle;
Opposite XY = 10
Adjacent YZ = 7
Hypotenuse XZ = √149
Using the SOH CAH TOA identity
sinZ = opp/hyp
sinZ =10/√149
sinZ = 7/√149
For cos Z
cosZ = 7/√149
Step-by-step explanation:
(3x² + 4x - 8) - (-2x² + 4x + 2)
[3 - (-2) = 5] , [ 4 - 4 = 0] , [ (-8) - 2 = -10]
5x² + 0x - 10
(or)
5x² - 10
Answer:
-1.53 , 1.53
Step-by-step explanation:
It is basically asking you to find the percentiles. so for the bottom 6.3% you would type into your calculator 2nd, VARS, invNorm, area: .063, mean: 0, and Standard Deviation: 1 which gives you -1.53.
for the upper 6.3% you have to take 1-.063=.937 to get the upper percentile. now type into your calculator 2nd, VARS, invNorm, area: .937, mean: 0, and Standard Deviation: 1 which gives you 1.53.
I hope I helped :D
