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sukhopar [10]
4 years ago
8

When constructing a graph that compares the land areas of the five largest countries, you choose to depict the five areas with s

quares of different sizes. If the squares are drawn so that the areas are in proportion to the areas of the corresponding countries, is the resulting graph valid? Why or why not?
No, using area in graphs is always misleading.


Yes, using area in graphs is never misleading.


Yes, the variable of interest is two-dimensional.


No, the variable of interest is two-dimensional.
Mathematics
2 answers:
Lerok [7]4 years ago
8 0
<h2>Answer:</h2>

The correct answer is:

      Yes, the variable of interest is two-dimensional.

<h2>Step-by-step explanation:</h2>

Since we know that the area of a land of five largest countries is two-dimensional.

Also , if we are using a square figure which is also two-dimensional in order to describe the area of land then it would be valid because we just used a mathematical model of equal dimension to describe these lands.

       Hence, the answer is:

     Yes, the variable of interest is two-dimensional.

Lera25 [3.4K]4 years ago
5 0
Yes, the variable of interest is two-dimensional.

If you are making a graph about the area of a country, that is a two dimensional measurement. It would be ok to make a graph that is also 2 dimensional.
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Anna007 [38]

Answer:

Part A: Angle R is not a right angle.

Part B; Angle GRT' is a right angle.

Step-by-step explanation:

Part A:

From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).

Slope formula

m=\frac{y_2-y_1}{x_2-x_1}

The product of slopes of two perpendicular lines is -1.

Slope of GR is

\text{Slope of GR}=\frac{1-5}{-3-(-6)}=\frac{-4}{3}

Slope of RT is

\text{Slope of RT}=\frac{6-1}{2-(-3)}=\frac{5}{5}=1

Product of slopes of GR and RT is

\frac{-4}{3}\times 1=\frac{-4}{3}\neq -1

Therefore lines GR and RT are not perpendicular to each other and angle R is not a right angle.

Part B:

If vertex T translated by rule

(x,y)\rightarrow(x-1,y-2)

Then the coordinates of T' are

(2,6)\rightarrow(2-1,6-2)

(2,6)\rightarrow(1,4)

Slope of RT' is

\text{Slope of RT'}=\frac{4-1}{1-(-3)}=\frac{3}{4}

Product of slopes of GR and RT' is

\frac{-4}{3}\times \frac{3}{4}=-1

Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.

6 0
3 years ago
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ludmilkaskok [199]
The area of the composite figure can be calculate

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2 years ago
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Answer: (-6, 5)

<u>Step-by-step explanation:</u>

Use the Midpoint Formula: \dfrac{(x_k, y_k)+(x_L,y_L)}{2}=(x_m, y_m)

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Answer:

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