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Elza [17]
3 years ago
7

How many ways can 4 candy bars be chosen from a store that sells 30 candy bars (combination)

Mathematics
2 answers:
SVEN [57.7K]3 years ago
7 0
Using the combination formula (<span><span>n!/</span><span>(r!(n−r)!)), you would get a total of</span></span><span> </span>27,405 combinations.
Morgarella [4.7K]3 years ago
3 0

Answer:

Using the combination formula:

Number of combination of r object chosen from the total object i.e n is given by:

\frac{n!}{r! \cdot (n-r)!}

As per the statement:

4 candy bars be chosen from a store that sells 30 candy bars

Number of candy bars chosen from a store that sells 30 candy bars(r)= 4

and

Total candy bars(n) = 30

then substitute in the given formula we have;

\frac{30!}{4! \cdot (30-4)!}

⇒\frac{30!}{4! \cdot (26)!}

⇒\frac{30 \cdot 29 \cdot 28 \cdot 27 \cdot 26!}{1 \cdot 2 \cdot 3 \cdot 4 \cdot (26)!}

Simplify:

⇒\frac{657720}{24} = 27,405

therefore, 27,405  ways can 4 candy bars be chosen from a store that sells 30 candy bars

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Serhud [2]
Sorry but im terrible at math
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3 years ago
EXAMPLE 5 If f(x, y, z) = x sin(yz), (a) find the gradient of f and (b) find the directional derivative of f at (1, 2, 0) in the
solong [7]

Answer:

<h2>a) f =  sin(yz)i + xzcos(yz)j + xycos(yz)k</h2><h2>b) -2</h2>

Step-by-step explanation:

Given f(x, y, z) = x sin(yz), the formula for calculating the gradient of the function is expressed as ∇f(x, y, z) = fx(x, y, z)i+ fy(x, y, z)j+fz(x, y, z)k where;

fx, fy and fz are the differential of the functions with respect to x, y and z respectively.

a) ∇f(x, y, z) = sin(yz)i + xzcos(yz)j + xycos(yz)k

The gradient of f =  sin(yz)i + xzcos(yz)j + xycos(yz)k

b) Directional derivative of f at (1,2,0) in the direction of v = i + 4j − k is expressed as ∇f(1, 2, 0)*v

∇f(1, 2, 0) = sin(2(0))i +1*0cos(2*0)j + 1*2cos(2*0)k

∇f(1, 2, 0) = sin0i +0cos(0)j + 2cos(0)k

∇f(1, 2, 0) = 0i +0j + 2k

Given v = i + 4j − k

∇f(1, 2, 0)*v (note that this is the dot product of the two vectors)

∇f(1, 2, 0)*v =  (0i +0j + 2k)*(i + 4j − k )

Given i.i = j.j = k.k =1 and i.j=j.i=j.k=k.j=i.k = 0

∇f(1, 2, 0)*v = 0(i.i)+4*0(j.j)+2(-1)k.k

∇f(1, 2, 0)*v = 0(1)+0(1)-2(1)

∇f(1, 2, 0)*v =0+0-2

∇f(1, 2, 0)*v= -2

 

Hence, the directional derivative of f at (1, 2, 0) in the direction of v = i + 4j − k is -2

7 0
3 years ago
What is the volume of a sphere with surface area of 25 pi yd squared?
kherson [118]

\bf \textit{surface area of a sphere}\\\\ SA=4\pi r^2~~ \begin{cases} r=radius\\ \cline{1-1} SA=25\pi \end{cases}\implies 25\pi =4\pi r^2 \\\\\\ \cfrac{25\pi }{4\pi }=r^2\implies \cfrac{25}{4}=r^2\implies \sqrt{\cfrac{25}{4}}=r\implies \cfrac{\sqrt{25}}{\sqrt{4}}=r\implies \cfrac{5}{2}=r \\\\[-0.35em] ~\dotfill

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}\qquad \qquad \implies V=\cfrac{4\pi \left( \frac{5}{2} \right)^3}{3}\implies V=\cfrac{4\pi \cdot \frac{125}{8}}{3}\implies V=\cfrac{\frac{500\pi }{8}}{~~\frac{3}{1}~~} \\\\\\ V=\cfrac{500\pi }{8}\cdot \cfrac{1}{3}\implies V=\cfrac{500\pi }{24}\implies V=\cfrac{125\pi }{6}\implies V\approx 65.45

7 0
3 years ago
Sin θ = 12/37. Find tan θ.
ivann1987 [24]

Answer:

B

Step-by-step explanation:

Use SOHCAHTOA.

sinθ = \frac{opposite}{hypotenuse}

Opposite side length= 12

Hypotenuse length = 37

Find the adjacent side length (b) using the Pythagorean theorem.

12^2 + b^2 = 37^2

b = 35

tanθ = \frac{opposite}{adjacent} = 12/35

Choice B is the correct answer.

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3 years ago
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seraphim [82]

Answer: y = 1/3x + 2

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