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Elza [17]
3 years ago
7

How many ways can 4 candy bars be chosen from a store that sells 30 candy bars (combination)

Mathematics
2 answers:
SVEN [57.7K]3 years ago
7 0
Using the combination formula (<span><span>n!/</span><span>(r!(n−r)!)), you would get a total of</span></span><span> </span>27,405 combinations.
Morgarella [4.7K]3 years ago
3 0

Answer:

Using the combination formula:

Number of combination of r object chosen from the total object i.e n is given by:

\frac{n!}{r! \cdot (n-r)!}

As per the statement:

4 candy bars be chosen from a store that sells 30 candy bars

Number of candy bars chosen from a store that sells 30 candy bars(r)= 4

and

Total candy bars(n) = 30

then substitute in the given formula we have;

\frac{30!}{4! \cdot (30-4)!}

⇒\frac{30!}{4! \cdot (26)!}

⇒\frac{30 \cdot 29 \cdot 28 \cdot 27 \cdot 26!}{1 \cdot 2 \cdot 3 \cdot 4 \cdot (26)!}

Simplify:

⇒\frac{657720}{24} = 27,405

therefore, 27,405  ways can 4 candy bars be chosen from a store that sells 30 candy bars

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