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Serjik [45]
3 years ago
15

Solve the given trigonometric equation analytically and by use of a calculator. Compare results. Use values of x for 0≤x≤2π

Mathematics
1 answer:
kodGreya [7K]3 years ago
8 0

Answer:

it can help you with answer a math problem

Step-by-step explanation:

You might be interested in
3/8=r+2/3 PLease help im really lazy
stira [4]

Answer:

- 7/24

Step-by-step explanation:

Step 1:

3/8 = r + 2/3

Step 2:

9/24 = r + 16/24

Step 3:

9/24 - 16/24 = r

Answer:

- 7/24 = r

Hope This Helps :)

5 0
3 years ago
Read 2 more answers
Of the entering class at a​ college, ​% attended public high​ school, ​% attended private high​ school, and ​% were home schoole
Veronika [31]

Answer:

(a) The probability that the student made the​ Dean's list is 0.1655.

(b) The probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c) The probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

<em>A</em> = a student attended public high school

<em>B</em> = a student attended private high school

<em>C</em> = a student was home schooled

<em>D</em> = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

(a)

The law of total probability states that:

P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})

Compute the probability that the student made the​ Dean's list as follows:

P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)

         =(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655

Thus, the probability that the student made the​ Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

P(B|D)=\frac{P(D|B)P(B)}{P(D)}

             =\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c)

Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

P(C^{c}|D^{c})=1-P(C|D^{c})

               =1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

3 0
3 years ago
In circle D, if the measure of arc Gec is 230 , what is the measure of minor arc GFC
BabaBlast [244]

Answer:

The measure of minor arc GFC is 130\°

Step-by-step explanation:

we know that

In a circle the sum of the major arc plus the minor arc is equal to 360 degrees

see the attached figure to better understand the problem

Let

x------> the major arc GEC

y-----> the minor arc GFC

so

x+y=360\°

we have

x=230\°

substitute in the equation and solve for y

230\°+y=360\°

y=360\°-230\°=130\°

8 0
4 years ago
HELP 13 POINTS!!!!!!!!!!!!!!!!!!
ahrayia [7]

Answer:

4^{-8} \\4^{-2}\\4^{8}\\4^2

Step-by-step explanation:

For the first few exponents multiply and the rest they add because like terms.

The trick is that when you raise a power to a power you multiply. Otherwise you add if the base value is the same.

5 0
3 years ago
Find the radius and diameter of a frisbee with a circumference of 11 pi inches.
nikdorinn [45]
Circumerence=2pir or dpi were r=radius and d=diameter
11pi=2pir
divid eobt sides by pi
11=2r
dvide 2
5.5=r

11pi=dpi
divide both sides by pi
11=d

diameter=11in
radius=5.5 in
6 0
4 years ago
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