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Sever21 [200]
3 years ago
10

(−6)∙(a+2b−3c−4d)−(−2)∙(−4a−3b+2c+d)

Mathematics
2 answers:
nasty-shy [4]3 years ago
5 0

Answer:

-14a-18b+22c+26d

Alik [6]3 years ago
4 0
<span>
(−6)∙(a+2b−3c−4d)−(−2)∙(−4a−3b+2c+d)
this will give us:
-6(a+2b-3c-4d)+2(-4a-3b+2c+d)
opening the parenthesis we get:
-6a-12b+18c+24d-8a-6b+4c+2d
putting like terms together we get
-6a-8a-12b-6b+18c+4c+24d+2d
simplifying the above we get
-14a-18b+22c+26d
the answer is :
</span>-14a-18b+22c+26d<span>

</span>
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(4n-3n^3)-(3n^3+4n) answer
Katen [24]
I hope this helps you

6 0
3 years ago
Triangle ABC is similar to triangle EFD. What scale factor is required to dilate triangle ABC so that it's image, A'B'C' , is co
Gnoma [55]
The answer choice is a
4 0
3 years ago
Sally is 1 year older than 3 times the age of joe.Chirs is 5 years younger than 6 times the age of joe.If sally and Chris are th
Sav [38]
S = sally C = Chris J = Joe
sally is one year older than 3 times the age of joe, so
s = 3j + 1
chris is 5 years younger than 6 times the age of jo, so
c = 6j - 5
sally and chris are the same age so
s = c so
3j + 1 = 6j - 5
-3j -3j
1 = 3j - 5
+5 +5
6 = 3j or
3j = 6
3j/3 = 6/3
j = 2

check
s = c
3(2) +1 = 6(2) - 5
6 + 1 = 12 - 5
7 = 7 correct✅
7 0
3 years ago
Read 2 more answers
Suppose that the value of a stock varies each day from $13 to $24 with a uniform distribution. (a) Find the probability that the
bogdanovich [222]

Answer:

a. P= 0.6364

b. P = 0.3636

c. Q = $21.25

d. P = 0.5

Step-by-step explanation:

given data

value of a stock varies = $13 to $24

solution

P (stock value is more than $17)

P = \frac{(24-17)}{(24-13)}

P =  \frac{7}{11}

P = 0.6364

and

P (value of the stock is between $17 and $21)

P = \frac{(21-17)}{(24-13)}

P = \frac{4}{11}

P = 0.3636  

and  

Let the upper quartile be Q

\frac{(24 - Q)}{(24 - 13)} = 0.25

\frac{(24 - Q)}{11} = 0.25

(24 - Q) = 2.75

so

Q = $21.25

and

P(X > 20 | X > 16)

P = \frac{(24-20)}{(24-16)}

P = \frac{4}{8}

P = 0.5

3 0
4 years ago
What's the value of506,087
Butoxors [25]

it is 24.75

I used a long division method to find the value of 50

06087

4 0
2 years ago
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