Answer:
D. No, because the sample size is large enough.
Step-by-step explanation:
The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
If the sample size is higher than 30, on this case the answer would be:
D. No, because the sample size is large enough.
And the reason is given by The Central Limit Theorem since states if the individual distribution is normal then the sampling distribution for the sample mean is also normal.
From the central limit theorem we know that the distribution for the sample mean
is given by:
If the sample size it's not large enough n<30, on that case the distribution would be not normal.
Answer: B. 140 cubic inches.
Step-by-step explanation:
The question is asking you to find the volume of the rectangular prism.
You can find this by using this formula:

Where w is the width, h is the height, and l is the length.
Substitute the sides of the rectangular prism into the equation:

The volume of the prism is 140 cubic inches.
The correct answer is B.
Answer:
oh thank you!
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Answer:
x > -9
Step-by-step explanation:
The solution to the inequality is obtained as follows:
-3x -7 < 20
-3x - 7 + 7 < 20 + 7
-3x < 27
-3x/(-3) > 27/(-3)
x > -9
Notice that when you divide by a negative number, the inequality sign changes.
In the picture attached, the graph of the solution s shown. Notice that -9 is not included in the solution.
Answer:
E = (1, 2)
Step-by-step explanation:
You want ...
(E -G) : (O -E) = 3 : 4
4(E -G) = 3(O -E) . . . . . . . . "cross multiply"
4E -4G = 3O -3E . . . . . . . . eliminate parentheses
7E = 4G + 3O . . . . . . . . . . . add 3E+4G
E = (4G +3O)/7 . . . . . . . . . .divide by 7
E = (4(-5, -1) +3(9, 6))/7 = (-20+27, -4+18)/7 = (7, 14)/7 . . . . fill in G and O
E = (1, 2)