There are 78 pennies and 53 nickels in the jar
<h3>System of linear equations</h3>
From the question, we are to determine the number of pennies and nickels in the jar
Let p represent the number of pennies
and
n represent the number of nickels
From the given information,
She counted them and found that there were 131 coins worth $3.43
Then, we can write that
p + n = 131 ---------- (1)
and
0.01p + 0.05n = 3.43 ---------- (2)
NOTE: 1 penny = $0.01
and
1 nickel = $0.05
Solve the two equations simultaneously
From equation (1)
p + n = 131
p = 131 - n --------- (3)
Substitute into the equation (2)
0.01p + 0.05n = 3.43
0.01(131 - n) + 0.05n = 3.43
1.31 - 0.01n + 0.05n = 3.43
- 0.01n + 0.05n = 3.43 - 1.31
0.04n = 2.12
n = 2.12/0.04
n = 53
Substitute the value of n into equation (3)
p = 131 - n
p = 131 - 53
p = 78
Hence, there are 78 pennies and 53 nickels in the jar
Learn more on System of Linear equations here: brainly.com/question/13729904
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