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julsineya [31]
3 years ago
8

PLEASE HELP ASAP!!! PLEASE HELP ASAP!!! PLEASE HELP ASAP!!! PLEASE HELP ASAP!!! PLEASE HELP ASAP!!! PLEASE HELP ASAP!!! PLEASE H

ELP ASAP!!! PLEASE HELP ASAP!!!

Mathematics
2 answers:
MrRa [10]3 years ago
7 0

Answer:

D

Step-by-step explanation:

jok3333 [9.3K]3 years ago
3 0
D) 7 8/9 gallons

hope this helps
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Ribbon a is 1/3. M long. It is 2/5 M shorter than ribbon B. How long is Ribbon B?
Volgvan

Ribbon B is \frac{11}{15} meters long

<em><u>Solution:</u></em>

Given that,

Ribbon A is 1/3 meter long. It is 2/5 meter shorter than ribbon B

To find: length of Ribbon B

From given information in question,

Length of Ribbon A = \frac{1}{3} \text{ meter }

Length of Ribbon A is 2/5 meter shorter than ribbon B

Therefore we can say,

Length of Ribbon A = length of ribbon B - \frac{2}{5}

\frac{1}{3} = \text{ length of ribbon B } -\frac{2}{5}\\\\\text{length of ribbon B } = \frac{1}{3} + \frac{2}{5}\\\\\text{length of ribbon B } = \frac{ 5 + 6}{15} = \frac{11}{15}

Therefore ribbon B is \frac{11}{15} meters long

4 0
3 years ago
Which expression is equivalent?
babymother [125]

Answer:

Third choice from the top is the one you want

Step-by-step explanation:

This whole concept relies on the fact that if the index of a radical exactly matches the power under the radical, both the radical and the power cancel each other out.  For example:

\sqrt[6]{x^6} =x and another example:

\sqrt[12]{2^{12}}=2

Let's take this step by step.  First we will rewrite both the numerator and the denominator in rational exponential equivalencies:

\frac{\sqrt[4]{6} }{\sqrt[3]{2} }=\frac{6^{\frac{1}{4} }}{2^{\frac{1}{3} }}

In order to do anything with this, we need to make the index (ie. the denominators of each of those rational exponents) the same number.  The LCM of 3 and 4 is 12.  So we rewrite as

\frac{6^{\frac{3}{12} }}{2^{\frac{4}{12} }}

Now we will put it back into radical form so we can rationalize the denominator:

\frac{\sqrt[12]{6^3} }{\sqrt[12]{2^4} }

In order to rationalize the denominator, we need the power on the 2 to be a 12.  Right now it's a 4, so we are "missing" 8.  The rule for multiplying like bases is that you add the exponents.  Therefore,

2^4*2^8=2^{12}

We will rationalize by multiplying in a unit multiplier equal to 1 in the form of

\frac{\sqrt[12]{2^8} }{\sqrt[12]{2^8} }

That looks like this:

\frac{\sqrt[12]{6^3} }{\sqrt[12]{2^4} }*\frac{\sqrt[12]{2^8} }{\sqrt[12]{2^8} }

This simplifies down to

\frac{\sqrt[12]{216*256} }{\sqrt[12]{2^{12}} }

Since the index and the power on the 2 are both 12, they cancel each other out leaving us with just a 2!  Doing the multiplication of those 2 numbers in the numerator gives us, as a final answer:

\frac{\sqrt[12]{55296} }{2}

Phew!!!

4 0
4 years ago
Using the transformation T: (x, y) (x + 2, y + 1), find the distance named.
kumpel [21]
A(0,0) A'(2,1)
distance(AA') = √(2^2 + 1^2)
= √5
= 2.24

answer
Distance AA' = √5 or = 2.24
4 0
3 years ago
Read 2 more answers
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zepelin [54]

Answer:

68 square unites

Step-by-step explanation:

Draw a live from (-8,2) to (0,2) and up to (0,4).  This divides it into three shapes.

Big triangle = 0.5x8x12=48

Little triangle = 0.5x2x4=4

Rectangle = 8x2=16

48+4+16=68

7 0
3 years ago
If we apply the Pythagorean Theorem to the Egyptian knots we can see that 3^2 + 4^2 = 5^2
o-na [289]

Answer:

d

Step-by-step explanation:

4 0
3 years ago
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