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Agata [3.3K]
3 years ago
10

How Many Square Meters Are There In 3000m2

Mathematics
1 answer:
uysha [10]3 years ago
7 0

Answer:

<em>1.Option: d.)3000m2 </em>

<em>2. Option: b.)5000cm3</em>

Step-by-step explanation:

<u>Area And Volume Units Conversion </u>

The area can be expressed in a variety of units like square meters, square inches, square kilometers, acres, hectare, etc. A similar situation happens with the volume, which can be expressed in units like cubic centimeters, cubic feet, cubic meters, liters, gallons, ounces, etc.  

1. The first part of the question gives nothing to do. The area is given in square meters and is requested in square meters, thus

3000\ m^2=3000\text{ square meters}

Option: d.)3000m2

2. One liter has 1000 cubic centimeters or 0.001 cubic meters, so

50\ lt= 50\times 1000=50,000\ cm^3

Option: b.)5000cm3

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20 PoINTS!!! The line graphed below has a slope of ____. -3 -1/3 1/3 3
qwelly [4]

Answer:

-3

Step-by-step explanation:

We have two points

( -3,1)  ( -1,-5)

We can use the slope formula

m = (y2-y1)/(x2-x1)

    = ( -5-1)/(-1- -3)

    = (-5-1) / (-1+3)

    = -6/2

    = -3

5 0
3 years ago
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HURRY! what is x? |4x + 7| +11=14
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Answer:

20

Step-by-step explanation:

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3 years ago
Find the zeros of the function (x+3)^2(x-5)^6 and state the multiplicity
nikklg [1K]
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3 0
4 years ago
Tanya made 75 flyers for five volunteers in her club to hang up around her school she gave 15 flyers to the first volunteer 22 f
AysviL [449]

Answer:

The remaining volunteers would get 11 flyers each.

Step-by-step explanation:

Given:

Total number of flyers = 75

Total number of volunteers = 5

Number of flyers for 1 volunteer = 15 flyers.

Number of flyers to 2nd volunteer = 22 flyers.

number of flyers to 3 volunteer = 16 flyers.

We need to find the remaining number of which are equally distributed in remaining number of volunteers.

Solution:

First we will find the number of flyers already distributed.

number of flyers already distributed is equal to sum of Number of flyers for 1 volunteer, Number of flyers for 2 volunteer and Number of flyers for 3 volunteer.

framing in equation form;

number of flyers already distributed = 15+22+16 = 53\ flyers

Number f flyers remaining is equal to Total number of flyers minus number of flyers already distributed.

Number of flyers remaining = 75-53= 22\ flyers

Number of volunteers remaining  =2

Now we will find number of flyers remaining each volunteers would get.

number of flyers remaining each volunteers would get is equal to Number of flyers remaining divided by Number of volunteers remaining.

framing in equation form we get;

number of flyers remaining each volunteers would get = \frac{22}{2}=11\ flyers

Hence the remaining volunteers would get 11 flyers each.

5 0
4 years ago
PLEASE HELP IM SO CONFUSED!!!
Step2247 [10]

Problem 1

The median weight of the Welsh corgis is 27 pounds. This is found in the table in row 1, column 2. Recall that the median is the middle most value, so that means 50% of the Welsh corgi weights will be less than 27 pounds, and also 50% of the weights are greater than 27 pounds.

========================================================

Problem 2

The Welsh corgis have the greater variation in weights. Why is this? There are two pieces of evidence:

The first of which is that the range for the first row (7) is larger than the range in the second row (2). The range is the difference between the max and min. The larger the range, the more spread out the data set will be.

The second piece of evidence is that the MAD (mean absolute deviation) for the Welsh corgis is larger compared to the MAD for the cocker spaniels group. The MAD is another way to measure the spread of a data set. Like the range, the larger the MAD gets, the more spread out the data is. It measures how far on average any given value is from the mean. It's similar to the standard deviation and variance, which are also measures of spread.

========================================================

Problem 3

Both dog breeds have the same mean value, and roughly the same median. Both the mean and median are measures of center. Based on just these two pieces of info alone, we could easily conclude that both dog groups have the same distribution more or less. Furthermore, we could conclude that both groups have roughly the same max weight value.

However, we discussed in problem 2 that the first group (Welsh corgi) is more spread out, so it's likely that could heavily imply that the min and max values are further from the center compared to the second group of dogs. Having a larger max would then mean that the corgi group has the largest weight.

In short, the answer is "Welsh corgi" due to this group having a greater spread, and that pushes the max further away from the center.

7 0
3 years ago
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