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2 years ago

How do you find the range on a box and whisker plot

Mathematics

1 answer:

faust18 [17]2 years ago

5 0

<span>the difference between the largest and smallest data values in a data set.</span>

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PLSS HELP IF YOU TURLY KNOW THISS

dangina [55]

Answer:

$\frac{0.3x - 2.1}{3} = 0.4 \\ 0.3x - 2.1 = 0.4 \times 3 \\ 0.3x - 2.1 = 0.12 \\ 0.3 x = 0.12 + 2.1 \\ 0.3x = 2.22 \\ x = \frac{2.22}{0.3} \\ x = 7.4$

6 0

2 years ago

Read 2 more answers

The following 5 questions are based on this information: An economist claims that average weekly food expenditure of households

liq [111]

Answer:

Null hypothesis: $\mu_{1}-\mu_{0}\leq 0$

Alternative hypothesis: $\mu_{1}-\mu_{2}>0$

$SE=\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}=2.705$

b) 2.70

$t=\frac{(164-159)-0}{\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}}=1.850$

b. 1.85

$p_v =P(Z>1.85)=0.032$

b. 0.03

a. We can reject H(0) in favor of H(a)

Step-by-step explanation:

Data given and notation

$\bar X_{1}=164$ represent the mean for the sample 1

$\bar X_{2}=159$ represent the mean for the sample 2

$\sigma_{1}=12.5$ represent the population standard deviation for the sample 1

$s_{2}=9.25$ represent the population standard deviation for the sample B2

$n_{1}=35$ sample size selected 1

$n_{2}=30$ sample size selected 2

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the expenditure of households in City 1 is more than that of households in City 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{0}\leq 0$

Alternative hypothesis: $\mu_{1}-\mu_{2}>0$

We know the population deviations, so for this case is better apply a z test to compare means, and the statistic is given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-0}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Standard error

The standard error on this case is given by:

$SE=\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}$

Replacing the values that we have we got:

$SE=\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}=2.705$

b. 2.70

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{(164-159)-0}{\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}}=1.850$

P-value

Since is a one side right tailed test the p value would be:

$p_v =P(Z>1.85)=0.032$

b. 0.03

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

a. We can reject H(0) in favor of H(a)

4 0

2 years ago

Area of square floor is 100 square centimeters,and the scale of the drawing is 1 centimeter:2ft,what is the area of the actual f

Taya2010 [7]

100 square centimeters means the dimensions are 10x10
but the actual floor will be 1cm:2ft
so 10cm=20feet
making the dimensions 20feetx20feet
the area of the actual floor is 400 feet

4 0

2 years ago

Round 392 to the nearest ten

Bezzdna [24]

Nearest 10 is according to the last digit.
if the digit is >5, it +1 to the tenth digit. If it's <5, it will be reduced to 0.

for your case, 392, 2 < 5, therefore rounded up to nearest tenth is 390.

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2 years ago

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Suppose you write a sum of numbers as a product of their GCF and another sum. What is the GCF of the numbers in the other sum? C

vivado [14]

Answer:

Step-by-step explanation:

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2 years ago