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expeople1 [14]
3 years ago
9

Sarah has made 30dresses, and she plans to make 3more dresses per month. Her sister , Anna has 40dresses and is planning on givi

ng away 2 dresses per month
After how many months will Sarah and Anna have the same number of dresses​
Mathematics
1 answer:
Elena L [17]3 years ago
4 0

Answer:

2 months

Step-by-step explanation:

you can set up equations for each sister:

(Sarah) y = 3x + 30

(Anna) y = -2x + 40

you can graph them to find where they intersect (2,36) or:

you can set them equal to each other like the following:

3x + 30 = -2x + 40

5x = 10

x = 2

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Step-by-step explanation:

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A small town has 2000 families. The average number of children per family is mu = 2.5, with a standard deviation sigma = 1.7. A
Nikitich [7]

Answer:

Let X the random variable that represent the number of children per fammili of a population, and for this case we know the following info:

Where \mu=2.5 and \sigma=1.7

We select a sample of n =64 >30 and we can apply the central limit theorem. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And for this case the standard error would be:

\sigma_{\bar X} = \frac{1.7}{\sqrt{64}}= 0.2125

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable that represent the number of children per fammili of a population, and for this case we know the following info:

Where \mu=2.5 and \sigma=1.7

We select a sample of n =64 >30 and we can apply the central limit theorem. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And for this case the standard error would be:

\sigma_{\bar X} = \frac{1.7}{\sqrt{64}}= 0.2125

6 0
3 years ago
1.
Alekssandra [29.7K]

Answer:

The number of visit so that both plan cost same is 10 .

Both the plan has equivalent choice of benefit

Step-by-step explanation:

Given as :

A gym has two membership plans.

For Gold plan

The charge per month = $50  

The charge per visit = $3

For Platinum plan

The charge per month = $20  

The charge per visit = $6

Let The number of visit for which each plan be same = n visits

Now, According to question

<u>∵ Each plan cost to be same</u>

So,

The charge per month for gold plan+ The charge per visit × numbers of visit = The charge per month for platinum plan+ The charge per visit × numbers of visit

I.e $50 + $3 × n = $20 + $6 × n

Or, $50 - $20 =  $6 × n  -  $3 × n

Or, $30 = ($6 - $3) × n  

Or, $30 = $3 × n  

∴ n = \dfrac{30}{3}

I.e n = 10

So, The number of visits = n = 10

Now, For Gold plan

The charge per month = $50  

The charge per visit = $3 × 10 = $30

So, Total charge for gold plan = $50 + $30 = $80

Similarly For Platinum plan

The charge per month = $20  

The charge per visit = $6×10 = $60

So, For Platinum plan ,total charge = $20 + $60 = $80

Hence, The number of visit so that both plan cost same is 10

and both the plan has equivalent benefit. Answer

4 0
3 years ago
Log 5 +3 log 2-log4÷log10<br>​
allsm [11]

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Hi my lil bunny!

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

Let's simplify step-by-step.

Log (5) + (3 log (2)) - \frac{log(4)}{log(10)}

= 0.69897 + 3(log (2)) - \frac{log (4)}{log (10)}

= 0.69897 + (3) (0.30103) - \frac{log (4)}{log(10)}

= 0.69897 + 0.90309 - \frac{log (4)}{log(10)}

= 1.60206 - \frac{log(4)}{log(10)}

= 1.60206 - \frac{1.60206}{log (10)}

= 1.60206 - \frac{1.60206}{1}

= 1.60206 - 0.60206

= 1

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Have a great day/night!

❀*May*❀

4 0
3 years ago
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