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tekilochka [14]
3 years ago
14

What is the mean of 87 104 and 99

Mathematics
2 answers:
sveticcg [70]3 years ago
6 0
It is 96.6 repeating. to get this answer, you add up all the numbers then divide the answer by hiw many numbers there are
Luden [163]3 years ago
6 0
87 + 104 + 99 = 290
290/3 (3 came from the amount of numbers there are) = 96.66...
You can also write as 96\frac{2}{3} or %96.66...
(HAVE TO INCLUDE THOSE DOTS)
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Im not sure if there right or not
alina1380 [7]
They are both correct.
7 0
2 years ago
Determine if the equation is linear 2x y=4,
Juliette [100K]
Determine whether each equation is a linear equation. ... –2x – 3 = y .... linear. 16. 4y. 2. + 9 = –4. SOLUTION: Since y is squared, the equationcannot be written in standard form.
4 0
3 years ago
An octagon has a perimeter of 28 units. What is the perimeter of the image of the octagon after the translation (x,y) → (x-7,y+
kow [346]

Answer:

https://www.caverna.k12.ky.us/userfiles/110/Classes/7142//userfiles/110/my%20files/study%20guide%20answer%20key%20(1).pdf?id=4059

Step-by-step explanation:

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6 0
2 years ago
A store has 40% off sale on headphones. With this discount, the price of one pair of headphones is $36.00
Nataliya [291]

40 % off means we pay 60 %  (must total 100%)

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7 0
3 years ago
Explain why S = {(5, 4, -2), (-15, -12, 6), (10, 8, -4)} is NOT a basis for R^3 (1 point Sis linearly dependent and spans R3 S i
earnstyle [38]

S would be a basis for \mathbb R^3 if

(1) the vectors in S are independent, and

(2) the vectors span \mathbb R^3.

  • Linear independence requires that c_1=c_2=c_3=0 is the only solution to

c_1(5,4,-2)+c_2(-15,-12,6)+c_3(10,8,-4)=(0,0,0)

These vectors are not linearly independent because if c_1=3, c_2=1, and c_3=0, we have

3(5,4,-2)+(-15,-12,6)=(15-15,12-12,-6+6)=(0,0,0)

so S is not a basis for \mathbb R^3.

7 0
3 years ago
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