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Leokris [45]
3 years ago
8

Factoer out the greatest common factor of 56^ - 49x + 14

Mathematics
1 answer:
babymother [125]3 years ago
6 0
56x² - 49x + 14 = 7(8x² - 7x +2)

_____
The greatest common factor of 56, 49, and 14 is 7.
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The answer is 4 right??
Step2247 [10]
Yes, you are correct. The answer to your problem is indeed 4.
7 0
3 years ago
in the equation dy+3x=2, for what value of d is the graph of the equation parallel to the graph of x-3y=0? the y axis?
IRISSAK [1]

Answer:

-9

Step-by-step explanation:

The slope of the the solving equation is triple the slope of the given equation. Therefore, the y coefficient must also be triple of the other y coefficient.

8 0
2 years ago
A veterinarian will prescribe an antibiotic to a dog based on its weight. The effective dosage of the antibiotic is given by d ≥
gregori [183]

Answer:

B) (35, 260)

Step-by-step explanation:

A veterinarian will prescribe an antibiotic to a dog based on its weight. The effective dosage of the antibiotic is given by d ≥ 1∕5w2, where d is dosage in milligrams and w is the dog's weight in pounds. Which of the following ordered pairs gives an effective dosage of antibiotics for a 35-pound dog?

A) (35, 240)

B) (35, 260)

C) (260, 35)

D) (240, 35)

Ordered pairs is composed of pairs, usually an x coordinate and a y coordinate. It refers to a location of a point on the coordinate. It matches numbers to functions or relations.

Given the relation between d is dosage in milligrams and w is the dog's weight in pounds as d ≥ 1∕5w²

For a 35 pound dog (i.e w = 35 pound). The dosage is given as:

d ≥ 1∕5(35)² ≥ 245 milligrams.

For an ordered pair (x, y), x is the independent variable (input) and y is the dependent variable (output).

The dog weight is the independent variable and the dosage is the dependent variable.

From the ordered pairs, the best option is (35, 260) because 260 ≥ 240

6 0
3 years ago
Solve |p + 2| = 10Solve |p + 2| = 10<br><br> {-12}<br> {-8, 8}<br> {-12, 8}
valentinak56 [21]

By definition, we have

|p+2| = \begin{cases} p+2 &\text{ if } p+2 \geq 0 \\-p-2 &\text{ if } p+2 < 0 \end{cases}

So, we have to solve two different equations, depending of the possible range for the variable. We have to remember about these ranges when we decide to accept or discard the solutions:

Suppose that p+2\geq 0 \iff p \geq -2

In this case, the absolute value doesn't do anything: the equation is

p+2 = 10 \iff p = 10-2 = 8

We are supposing p \geq -2, so we can accept this solution.

Now, suppose that p+2 < 0 \iff p < -2. Now the sign of the expression is flipped by the absolute value, and the equation becomes

-p-2 = 10 \iff -p = 12 \iff p = -12

Again, the solution is coherent with the assumption, so we can accept this value as well.

3 0
3 years ago
(05.06)Which interval on the graph could be described as linear constant?
Yakvenalex [24]
Segment A is a linear constant.  In general a linear constant will be y=k for a horizontal line or x=k for a vertical line.
8 0
3 years ago
Read 2 more answers
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