1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Artemon [7]
2 years ago
11

Im bad at composite figures || please hurry

Mathematics
1 answer:
goldfiish [28.3K]2 years ago
3 0

The figure is the combination of trapezoid and square. Then the area of the figure will be 39 square meters.

The complete question is attached below.

<h3>What is Geometry?</h3>

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

The figure is the combination of trapezoid and square.

Then the area of the geometry will be

Area = Area of trapezoid + Area of square

Area = 1/2 x (3 + 9) x 5 + 3 x 3

Area = 30 + 9

Area = 39 square meters

More about the geometry link is given below.

brainly.com/question/7558603

#SPJ1

You might be interested in
Which equation is equivalent to x^2 + 36x = 88?
just olya [345]

Answer:

C

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Holly scored an 88, 91, 89, 84, and a 98 on the last five math tests. What is her mean test score?
zaharov [31]

Answer:the mean is 90

Step-by-step

you find the sum of the values then divide them by the amount of numbers in the set

7 0
2 years ago
Find the area of the shaded region.
MariettaO [177]

Answer:

Area of  shaded region = 134.13 square feet

Step-by-step explanation:

Area of the shaded region = Area of square - Area of circle

                                         = ( 25 \times 25) - ( \pi 12.5^2)\\= 625 - 490.87\\= 134.13 ft^2

8 0
2 years ago
In the number 8,888.888, how does the 8 in the hundredths place compare to the 8 in the place to its left? A. The 8 in the hundr
prohojiy [21]
The answer is to the question is D.


4 0
3 years ago
Read 2 more answers
If PQ=8 and Q lies at -13 where could P be located?
choli [55]

Answer:

In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).

Step-by-step explanation:

There is really no need to use any quadratics or roots.

( Consider the same problem on the plain number line first.  )

How do you find the number between 2 and 5 which is twice as far from 2 as from 5?

You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get

4=2+23(5−2)

It works completely the same with geometric points (using vector operations), just linear interpolation: Call the result R, then

R=P+23(Q−P)

so in your case we get

R=(0,−1)+23(3,3)=(2,1)

Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)

Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get

s=a+b=2b+b=3b

⇔b=13s⇒a=23s

7 0
3 years ago
Other questions:
  • Give right answer quick!!!!
    13·1 answer
  • -4x +39 &gt; -29 what is the answer for this question
    8·1 answer
  • How do you subtract 9 2/6 - 6 5/6 =
    11·2 answers
  • Anybody please help me with this
    10·2 answers
  • Find the remainder when f(x) = x3 − 14x2 + 7x − 10 is divided by x − 3.
    5·1 answer
  • The sum of 4 consecutive integers is 122. What is the third number in this sequence?
    13·1 answer
  • (3, -2) belongs to the solution set of the system of inequalities given below:
    14·1 answer
  • 14. NUTRITION A cookie contains 9 grams of fat. If you eat no fewer than 4 and no more than 7 cookies, how many grams of fat wil
    9·1 answer
  • cannonball is shot into the air. its height can be described by the equation h = -5t2 + 40t, where h is the height in feet and t
    11·1 answer
  • I need help with this please
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!