3 years ago

Need help asap im not good at math

Mathematics

1 answer:

katovenus [111]3 years ago

6 0

most likely A,C,D,E 70% sure

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KL = 8x-5 and LM = 6x+3

Burka [1]

The answer is x=4.
set the equations up: 8x-5=6x-3
Subtract 6x from one side and then the other side 2x-5=3
Add 5 from one side and then the other 2x=8
Divide 2 on each side which gets you x=4

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3 years ago

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What is the factored form of the expression?Factor completely. 6x^4-9x^3-36x^2+54x

mario62 [17]

If we factorize the expression

$6x^4-9x^3-36x^2+54x$

We will get

$3x(2x-3)(x^2-6)$

Hope I helped!

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3 years ago

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Oints (2,5 and 8,4

Zanzabum

The slope for the question is -1.5

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2 years ago

Please help me with this

Ne4ueva [31]

Answer:

Option c

Step-by-step explanation:

A system of equations are given to us. And we need to solve them . The given system is

$\begin{cases} y = 2x - 3\dots 1 \\ y = x^2 - 3\dots 2 \end{cases}$

We numbered the equations here . Now put the value of equation 1 in equation 2 that is substituting y = 2x - 3 in eq. 2 .

$\implies y = x^2 - 3 \\\\\implies 2x - 3 = x^2 - 3 \\\\\implies x^2 - 2x = 0 \\\\\implies x(x-2) = 0 \\\\\implies\red{ x = 0 , 2 }$

We got two values of x as 0 & 2 . Alternatively substituting these values we have ,

$\implies y = 2 x - 3 \\\\\implies y = 2(0)-3 \qquad or \qquad y = 2(2)-3 \\\\\implies y = 0-3 \qquad or \qquad 4 - 3 \\\\\implies \red{ y = -3 , 1 }$

Thefore the required answer is ,

$\red{Option\:c} \begin{cases} (0,-3) \\ (2,1) \end{cases}$

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2 years ago

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alekssr [168]

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