1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mashcka [7]
2 years ago
7

You measure 50 textbooks' weights, and find they have a mean weight of 37 ounces. Assume the population standard deviation is 5.

2 ounces. Based on this, construct a 90% confidence interval for the true population mean textbook weight. Give your answers as decimals, to two places
Mathematics
1 answer:
Hoochie [10]2 years ago
7 0

Answer:

90% confidence interval for the true population mean textbook weight is [35.79 ounces , 38.21 ounces].

Step-by-step explanation:

We are given that you measure 50 textbooks' weights, and find they have a mean weight of 37 ounces.

Assume the population standard deviation is 5.2 ounces.

Firstly, the Pivotal quantity for 90% confidence interval for the population mean is given by;

                           P.Q. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean weight = 37 ounces

           \sigma = population standard deviation = 5.2 ounces

           n = sample of textbooks = 50

           \mu = true population mean textbook weight

<em>Here for constructing 90% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

<u></u>

<u>So, 90% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.645 < N(0,1) < 1.645) = 0.90  {As the critical value of z at 5%

                                            level of significance are -1.645 & 1.645}  

P(-1.645 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.645) = 0.90

P( -1.645 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.645 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.90

P( \bar X -1.645 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X +1.645 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X -1.645 \times {\frac{\sigma}{\sqrt{n} } } , \bar X +1.645 \times {\frac{\sigma}{\sqrt{n} } } ]

                                          = [ 37-1.645 \times {\frac{5.2}{\sqrt{50} } } , 37+1.645 \times {\frac{5.2}{\sqrt{50} } } ]

                                          = [35.79 , 38.21]

Therefore, 90% confidence interval for the true population mean textbook weight is [35.79 ounces , 38.21 ounces].

You might be interested in
a carpenter cut four lengths of wood. the lengths were 36 3/4 in., 36 3/8 in., 37 1/2., and z in. if the mean of lengths is 36 5
lisov135 [29]
36 3/4 = 36.75
36 3/8 = 36.375
37 1/2 = 37.5
36 5/8 = 36.625

(36.75 + 36.375 + 37.5 + z) / 4 = 36.625
(110.625 + z) / 4 = 36.625
110.625 + z = 36.625 * 4
110.625 + z = 146.5
z = 146.5 - 110.625
z = 35.875 or 35 7/8 <===
6 0
3 years ago
Please answer! I crossed out the ones you don’t have to complete.
Nina [5.8K]

Answer:

1. Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

5.  x^-6 = \frac{1}{x^6}

6. 5^{-3}.3^{-1}=\frac{1}{5^3.3^1}

7. a^{-3}b^0c^4=\frac{c^4}{a^3}

Step-by-step explanation:

Question 1:

We need to rewrite the expression using exponents

5.a.b.b.5.c.a.b.5.b

We will first combine the like terms

5.5.5.a.a.b.b.b.b.c

Now, if we have 5.5.5 we can write it in exponent as: =5^{1+1+1}=5^3

a.a as a^{1+1}=a^2

b.b.b.b as: b^{1+1+1+1}=b^4

So, our result will be:

5^3a^2b^4c

Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

Question:

Rewrite using positive exponent:

The rule used here will be: a^{-1}=\frac{1}{a^1} which states that if we need to make exponent positive, we will take it to the denominator.

Applying thee above rule for getting the answers:

5) x^{-6} = \frac{1}{x^6}

6) 5^{-3}.3^{-1}=\frac{1}{5^3.3^1}

7) a^{-3}b^0c^4=\frac{b^0c^4}{a^3}

We know that b^0=1 so, we get

a^{-3}b^0c^4=\frac{b^0c^4}{a^3}=\frac{c^4}{a^3}

4 0
3 years ago
19/24 as a decimal rounded to the nearest hundreths
Evgen [1.6K]

Answer:

0.79

Step-by-step explanation:

19 / 24 is 0.79166667

So it's 0.79

8 0
3 years ago
Find the next two numbers in the pattern. 9,-27,81,-243....
slava [35]

The answer is 729, -2187

because you multiply each number by -3



6 0
2 years ago
Write the equation y=-1/2x+3 in standard form.
cricket20 [7]
Begin by multiplying both sides by 2 to get rid of the fraction.  The standard form for a line is Ax + By = C, no fractions allowed.  By multiplying we get 2y=-1x+3.  Now move the -1x over by adding and we have the standard form we are looking for: x + 2y = 3.
7 0
3 years ago
Other questions:
  • Please help this is the last question!
    9·1 answer
  • ⚡️⚡️⚡️⚡️⚡️⚡️⚡️⚡️⚡️⚡️⚡️⚡️
    7·2 answers
  • What is 5,570,000 in scientific notation
    8·2 answers
  • Briana spent 2 3/4 hours on her science project. Jackson worked 1 1/3 times as long on his science project as Briana worked. For
    9·1 answer
  • What is the value of y if x = -0.6?<br> A. -3<br> B. -2<br> C. 0 <br> D. 3
    13·2 answers
  • John bought a new home in 2002. The value of the home increases 4% each year. If the price of the house is $375,000 in 2020, how
    11·1 answer
  • Whole numbers from 1 to 10 are placed in a bag. Olga picks two cards at once at random from the bag. What is the
    14·1 answer
  • DJ Davon is making a playlist for work; he is trying to decide what 12 songs to play and in what order they should be played. If
    9·1 answer
  • What is 5[6 1 2 -6]-[1 6 -6 6] matrix?
    8·2 answers
  • A person invest 7900 in an account growing at a rate allowing the money to double every 8 years. How much money would be in the
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!