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Mashcka [7]
3 years ago
7

You measure 50 textbooks' weights, and find they have a mean weight of 37 ounces. Assume the population standard deviation is 5.

2 ounces. Based on this, construct a 90% confidence interval for the true population mean textbook weight. Give your answers as decimals, to two places
Mathematics
1 answer:
Hoochie [10]3 years ago
7 0

Answer:

90% confidence interval for the true population mean textbook weight is [35.79 ounces , 38.21 ounces].

Step-by-step explanation:

We are given that you measure 50 textbooks' weights, and find they have a mean weight of 37 ounces.

Assume the population standard deviation is 5.2 ounces.

Firstly, the Pivotal quantity for 90% confidence interval for the population mean is given by;

                           P.Q. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean weight = 37 ounces

           \sigma = population standard deviation = 5.2 ounces

           n = sample of textbooks = 50

           \mu = true population mean textbook weight

<em>Here for constructing 90% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

<u></u>

<u>So, 90% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.645 < N(0,1) < 1.645) = 0.90  {As the critical value of z at 5%

                                            level of significance are -1.645 & 1.645}  

P(-1.645 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.645) = 0.90

P( -1.645 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.645 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.90

P( \bar X -1.645 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X +1.645 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X -1.645 \times {\frac{\sigma}{\sqrt{n} } } , \bar X +1.645 \times {\frac{\sigma}{\sqrt{n} } } ]

                                          = [ 37-1.645 \times {\frac{5.2}{\sqrt{50} } } , 37+1.645 \times {\frac{5.2}{\sqrt{50} } } ]

                                          = [35.79 , 38.21]

Therefore, 90% confidence interval for the true population mean textbook weight is [35.79 ounces , 38.21 ounces].

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