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3 years ago

There is a strong positive liner correlation between rainfall....

Mathematics

1 answer:

atroni [7]3 years ago

3 0

I’m pretty sure that a is the answer

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Find the constant of variation k for the direct variation

MAVERICK [17]

F(x) = a.x . We ha to calculate a.

Back to the table, let's rewrite the coordinates

A(0,0)
B(2,-1)
C(4,-2)
D(7,-3.5)
We know that constant is called slope or coefficient is equal to:
a=y/x
Apart from A, in each of the coordinates y/x =-1/2 & this is the slope of the equation f(x) = (-1/2)x

8 0

3 years ago

Disorder is to chaos as interest is to

san4es73 [151]

Answer: income

Step-by-step explanation: i just remembered it

Hope this helps and your welcome

Have a nice day

5 0

3 years ago

Read 2 more answers

Using the arrows, move the letters in the left column up or down to place them in the correct order from top to

Ivenika [448]

Answer:

c, d, a, b.

Step-by-step explanation:

I'm presuming that the original equation is $7c+\frac{k}{2}=15$ .

First, isolate c. You can do this by subtracting $\frac{k}{2}$ from both sides: $7c+\frac{k}{2}-\frac{k}{2}=15-\frac{k}{2}$

Next, simplify to $7c=15-\frac{k}{2}$ .

Then, divide both sides by 7: $\frac{7c}{7}=\frac{15-\frac{k}{2}}{7}$

Finally, simplify to $c=\frac{15}{7}-\frac{k}{14}$ .

6 0

3 years ago

Find the time it takes for a rocket following the path, h(x) = - 3x2 + 18x, to reach a maximum. In your final answer, include al

Georgia [21]

Answer:

it is 108

Step-by-step explanation:

8 0

3 years ago

A sum of $4200 was invested, part at 8% and the remainder at 11%. If $426.00 was earned in interest after one year, how much was

enot [183]

Answer:

$3000 was invested at 11%.

Step-by-step explanation:

The total interest was $426. This was comprised of interest earned at 8% (represented by e) and (separately) interest earned at 11% (represented by v).

Then e + v = $4200 total investment, and

i = $426 = e(0.08)(1 year) + v(0.11)(1 year)

We eliminate the variable e as follows: since e + v = $4200, e = $4200 - v. Thus,

i = $426 = e(0.08)(1 year) + v(0.11)(1 year) becomes:

i = $426 = ($4200 - v)(0.08)(1 year) + v(0.11)(1 year)

This is one equation in one unknown, the amount of $ invested at 11%.

Performing the indicated multiplications:

426 = 4200(0.08) - 0.08v + 0.11v. Simplifying this further, we get:

426 = 336 + 0.03v.

Then 90 = 0.03v, and v = 90 / 0.03 = $3000.

$3000 was invested at 11%.

6 0

3 years ago