Answer:
it would be 58
Step-by-step explanation:
if you do 72 x 417 it would be 5 at the top and 360 would be at the bottom so it would be 417-360 which is 57 and the six at the top u would drop so now it is 576 so if you do 72 x 8 it would be 576 so u would put the 8 with the 5 and subtract the 576 - 576 and that is 0 BOOM
(x1, y1) = (-3,-8)
(x2,y2)=(6,0)
Two point form
(y-0)=(0+8)/(6+3)*(x-6)
9y=8x-48
Answer:
x < -10
Step-by-step explanation:
Solve the inequality.
-2x + 4 > 24 Subtract 4 from both sides
-2x > 20 Divide both sides by -2
x < -10 We must flip the inequality sign because we divided by a negative number in the last step.
When you graph, draw a number line. Then, draw a circle on top of -10. Since x is less than -10, the arrow goes to the left of -10. Additionally, the circle on top of -10 will be an open circle because the inequality sign is a less than, not a less than or equal to.
I hope this helps and please mark me as brainliest!
Answer:
34 + 35 + 36 = 105
Step-by-step explanation:
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 105
3X + 3 = 105
3X + 3 - 3 = 105 - 3
3X = 102
3X/3 = 102/3
X = 34
Which means that the first number is 34, the second number is 34 + 1 and the third number is 34 + 2. Therefore, three consecutive integers that add up to 105 are 34, 35, and 36.
34 + 35 + 36 = 105
We know our answer is correct because 34 + 35 + 36 equals 105 as displayed above.
Let's say "p" people were going to the expedition initially, and the cost for each was "c", now, we know the total cost is 1800, so for "p", folks that'd be 1800/p how much each one cost, namely, how many times "p" goes into 1800.
well, prior to leaving, 15 dropped out, so that leaves us with " p - 15 ", and the cost "c" bumped up to " c + 27 " for each.
![\bf 1800p=1800(p-15)+27[p(p-15)] \\\\\\ 1800p=1800p-27000+27(p^2-15p) \\\\\\ 0=-27000+27(p^2-15p)\implies 0=-27000+27p^2-405p \\\\\\ \textit{now, let's take a common factor of }27 \\\\\\ 0=p^2-15p-1000\implies 0=(p-40)(p+25)\implies p= \begin{cases} \boxed{40}\\ -25 \end{cases}](https://tex.z-dn.net/?f=%5Cbf%201800p%3D1800%28p-15%29%2B27%5Bp%28p-15%29%5D%0A%5C%5C%5C%5C%5C%5C%0A1800p%3D1800p-27000%2B27%28p%5E2-15p%29%0A%5C%5C%5C%5C%5C%5C%0A0%3D-27000%2B27%28p%5E2-15p%29%5Cimplies%200%3D-27000%2B27p%5E2-405p%0A%5C%5C%5C%5C%5C%5C%0A%5Ctextit%7Bnow%2C%20let%27s%20take%20a%20common%20factor%20of%20%7D27%0A%5C%5C%5C%5C%5C%5C%0A0%3Dp%5E2-15p-1000%5Cimplies%200%3D%28p-40%29%28p%2B25%29%5Cimplies%20p%3D%0A%5Cbegin%7Bcases%7D%0A%5Cboxed%7B40%7D%5C%5C%0A-25%0A%5Cend%7Bcases%7D)
well, you can't have a negative value of people... so it has to be 40.
so, 40 folks were initially going, then 15 dropped out, how many went on the expedition? 40 - 15.
