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scoundrel [369]
4 years ago
7

Evaluate this expression

Mathematics
2 answers:
rjkz [21]4 years ago
6 0

Answer:

0

Step-by-step explanation:

We are given the expression:

2(a+3)/b

We know that a= -3 and b=2. Therefore, we can substitute -3 in for a and 2 in for b.

2(-3+3)/2

Now, solve according to PEMDAS: Parentheses, Exponents, Multiplication, Addition, Subtraction.

Solve inside the parentheses first. Add -3 and 3.

2(0)/2

Multiply 2 and 0.

0/2

Divide 0 by 2

0

Nitella [24]4 years ago
3 0

Answer:

0

Step-by-step explanation:

2(a+3)/b

Let a=-3 and b=2

2(-3+3) / 2

2(0)/2

0/2

0

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In a square, the sum of the lengths of three sides is 45 and in a rectangle the difference between a length and a width is 5 in.
stira [4]
Square:
We know all sides of a squares are equal in length.
s= the length of one side of the square.
45= s+s+s
45= 3s
s=15 inches
Each side of the square is 15 inches.

Rectangle:
length(l)= ????
Width(w)= s = 15 inches

l -w= 5inches
l- (15 inches)= 5 inches
l = 20 inches


Answer:
A length of the rectangle is 20 inches long.
5 0
3 years ago
Solve for the roots in the equation below. In your final answer, include each of the necessary steps and calculations. Hint: Use
QveST [7]
\bf 27\implies 3^3\\\\
i^3\implies i\cdot i\cdot i\implies i^2\cdot i\implies -1\cdot i\implies -i\\\\
-----------------------------\\\\
x^3-27i=0\implies x^3+3^3(-i)=0\implies x^3+(3^3i^3)=0
\\\\\\
x^3+(3i)^3=0\\\\
-----------------------------\\\\
\textit{difference of cubes}
\\ \quad \\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
(a+b)(a^2-ab+b^2)= a^3+b^3\\\\
-----------------------------\\\\

\bf (x+3i)[x^2-3ix+(3i)^2]=0\implies 
\begin{cases}
x+3i=0\implies \boxed{x=-3i}\\\\
x^2-3ix+(3i)^2=0
\end{cases}
\\\\\\
\textit{now, for the second one, we'd need the quadratic formula}
\\\\\\
x^2-3ix+(3i)^2=0\implies x^2-3ix+(3^2i^2)=0


\bf x^2-3ix+(-9)=0\implies x^2-3ix-9=0
\\\\\\
\textit{quadratic formula}\\\\
x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}\implies x=\cfrac{3i\pm\sqrt{(-3i)^2-4(1)(-9)}}{2(1)}
\\\\\\
x=\cfrac{3i\pm\sqrt{(-3)^2i^2+36}}{2}\implies x=\cfrac{3i\pm\sqrt{-9+36}}{2}
\\\\\\
x=\cfrac{3i\pm\sqrt{27}}{2}\implies \boxed{x=\cfrac{3i\pm 3\sqrt{3}}{2}}
7 0
3 years ago
I need the answer. Please help.
loris [4]

Answer:

44 degrees

Step-by-step explanation:

These segments form a triangle which is equal to 180 degrees. Since it forms a tangent to the circle, it forms a perpendicular angle with measure 90 degrees.

So 180 - 90 - 46 = Angle J

90 - 46 = Angle J

44 = Angle J

7 0
3 years ago
Please help I will give brainliest
wel

Answer:

i cant see the picture with the question

Step-by-step explanation:

i cant see, sorry

3 0
3 years ago
:
Scorpion4ik [409]

Answer:

  x-intercept: (4, 0)

  y-intercept: (0, 3)

Step-by-step explanation:

The intercepts of the equation can be found by setting each variable to zero and solving for the other. The graph will be a line through the intercept points.

<h3>Intercepts</h3>

Setting x=0 and solving for y, we have ...

  4y -12 = 0   ⇒   y = 12/4 = 3

Setting y=0 and solving for x, we have ...

  3x -12 = 0   ⇒   x = 12/3 = 4

The intercepts are ...

  x-intercept: (4, 0)

  y-intercept: (0, 3)

<h3>Graph</h3>

The line will go through these intercept points.

3 0
2 years ago
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