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sveticcg [70]
3 years ago
5

Jillian bought 1/2 pound of turkey and 1 1/3 pounds of cheddar cheese at the store.both items are on sale $6 per pound.how much

does the turkey and cheese cost?
Mathematics
1 answer:
olchik [2.2K]3 years ago
8 0
10 dollars is ther answer
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A car travels 320 miles on 15 gasoline. The best estimate if the cars mile per gallon is
Dovator [93]

Answer:

21.333 miles per gallon

Step-by-step explanation:

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3 years ago
Jim’s allowance is $1.20 per week. Stan’s is 25¢ per day. How long will they have to
algol [13]
First, find out how much stan gets per week. 

.25 x 7 =1.75

now how much they get together

1.75 + 1.20 = 2.95

and then the final step

23.60 / 2.95 = 8

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6th grade math help me, please:))
Leokris [45]

Answer:

40 percent

Step-by-step explanation:

(10/25 ) x 100 = (2/5) x100 = (0.4) x 100 = 40% of the roses was given away.

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3 years ago
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(-2,-1)

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6 0
3 years ago
Suppose there are two lakes located on a stream. Clean water flows into the first lake, then the water from the first lake flows
never [62]

Answer:

a.  For the first lake;

c = (m·t - 0.005·m·t²)/100000

For the second tank, we have;

c = m·t/200 - m·t²/80000

b. t ≈ 1.00505 hours

c. 200 hours

Step-by-step explanation:

The flow rate of water in and out of the lakes = 500 liters/hour

The volume of water in the first lake = 100 thousand liters

The volume of water in the second lake = 200 thousand liters

The mass of toxic substances that entered into the first lake =  500 kg

The concentration of toxic substance in the first lake = m₁/(100000)

Therefore, we have;

The quantity of fresh water supplied at t hours = 500 × t

The change

The change in the mass of the toxic substance with time is given as follows

dm/dt = (m - m/100000 × 500 × t)/100000

c = (m·t - 0.005·m·t²)/100000

For the second tank, we have;

c = m/100000 × 500 × t - (m/100000 × 500 × t)/200000 × 500 × t

Using an online tool, we have;

c = m·t/200 - m·t²/80000

b. When c < 0.001 kg per liter, we have m < 0.001 × 100000, which gives m < 100

Substituting gives;

0.001 = (100·t - 0.005·100·t²)/100000, solving with an online tool, gives;

t ≈ 1.00505 hours

c. For maximum concentration, we have;

c = m·t/200 - m·t²/80000

m/200000 = m·t/200 - m·t²/80000

1/200000 = t/200 - t²/80000

dc/dt = d(t/200 - t²/80000)/dt = 0

Solving with an online tool gives t = 200 hours

6 0
3 years ago
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