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IgorC [24]
4 years ago
11

Quick picture to find 3 x 2.7

Mathematics
1 answer:
Sav [38]4 years ago
8 0
The answer is 8.1
.........................

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Convert 50°F to Celsius.<br> _____ °C
Elan Coil [88]
10 Celsius
Explanation: SIRI said
3 0
3 years ago
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(The question is in the photo)
Naddik [55]

Answer:

6.99

Step-by-step explanation:

11.99+2.99+5.99=20.97

20.97/3=6.99

6 0
3 years ago
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Houw would i factor this problem out completely?
kvasek [131]
You can factor out a 3t first, resulting in:
3t(2t^2+3t-5)

Now, let's factor the equation in the middle using the quadratic equation. Plug in the values to the quadratic equation:
\frac{-3\pm \sqrt{3^2-4(2)(-5)}}{2(2)} = -\frac{3\pm \sqrt{49}}{4} = -\frac{3\pm 7}{4}

Simplify, you get your x's:
x = 1, -\frac{5}{2}

To write the equation in simplified form, you just write it this way:
3t(x-1)(2x+5)

That's your answer ^
3 0
3 years ago
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X - 5 = 20 <br> x= <br><br> I need to know what the x equals
Monica [59]

Answer:

x = 25

Step-by-step explanation:

Given

x - 5 = 20 ( isolate x by adding 5 to both sides )

x = 25

5 0
3 years ago
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Rewrite the system of linear equations as a matrix equation AX = B.
iren2701 [21]

Answer:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

Eq. 2 : x1 + x2 + x3 = 6

E1. 3 : 4x1 + 6x2 + 5x3 = 7

Coefficients for x1 ; x2 ; x3

From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]

And the vector of vriables (X) is:

\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

In conclusion, AX=B is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

7 0
4 years ago
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