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3 years ago

Can someone please help me!!

Mathematics

1 answer:

grandymaker [24]3 years ago

3 0

Answer:

rotation 90° CW about the origin we defined

Step-by-step explanation:

The image has the same orientation (clockwise order of vertices) as the pre-image, so an even number of reflections is involved. These cannot be reflections across the x- or y-axes. The longest edge has an east-west orientation in the pre-image and a south-north orientation in the image. Any reflections must have a net effect of a rotation 90° CW.

Equivalently, the image is rotated 90° clockwise from the pre-image.

With a suitable choice of center of rotation, the image can be obtained with a single 90° CW rotation transformation.

If we define the lower left corner of the pre-image as having coordinates (-1, 2), then a 90° CW rotation about (0, 0) will yield the image.

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Which order pair could represent the location of point h

Rus_ich [418]

What does the work look like first

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3 years ago

4. Write an equation for the line that is parallel to the given line and that passes

pentagon [3]

Answer:

$y=\frac{5}{2}x-14$

Step-by-step explanation:

Hi there!

What we need to know:

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x is 0)
Parallel lines always have the same slope

1) Determine the slope (m)

$y=\frac{5}{2}x-10$

In the given equation, $\frac{5}{2}$ is in the place of m, making it the slope. Because parallel lines have the same slope, the line we're currently solving for therefore has a slope of $\frac{5}{2}$ . Plug this into $y=mx+b$ :

$y=\frac{5}{2}x+b$

2) Determine the y-intercept (b)

$y=\frac{5}{2}x+b$

Plug in the given point (-6,-29) and solve for b

$-29=\frac{5}{2}(-6)+b$

Simplify -6 and 2

$-29=\frac{5}{1}(-3)+b\\-29=(5)}(-3)+b\\-29=-15+b$

Add 15 to both sides to isolate b

$-29+15=-15+b+15\\-14=b$

Therefore, the y-intercept is -14. Plug this back into $y=\frac{5}{2}x+b$ :

$y=\frac{5}{2}x-14$

I hope this helps!

4 0

3 years ago

For each part of this problem, show all your work and write a probability statement.

AlladinOne [14]

Answer:

Follows are the answer to the given point.

Step-by-step explanation:

In point 1:

$\to P( \text{number of response}) = \frac{192}{338} \\$

$= \frac{96}{169}\\\\= 0.56$

In point 2:

$\to P| \text{(Zoloft and fill response)}| = \frac{27}{338}$

$= 0.079$

In point 3:

$\to P(\frac{\text{ full or partial}}{\text{St. John's Wort}}) = \frac{\frac{43}{338}}{\frac{113}{338}}$

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In point 4:

$\to P(\frac{\text{Placebo}}{\text{full or response}}) = P(\frac{(\text{Placebo} \cap \text{full or response})} {\text{p(full response)}})$

$= \frac{\frac{79}{338}}{ 1- \frac{91}{338}} \\\\ = \frac{\frac{79}{338}}{ \frac{338-91}{338}} \\\\ = \frac{\frac{79}{338}}{\frac{247}{338}} \\\\ = \frac{79}{338} \times \frac {338}{247} \\\\= \frac{79}{274} \\\\ = 0.28$

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3 years ago

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Answer:

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