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2 years ago

Subtract 15 –k from -6k– 7.

Mathematics

1 answer:

NikAS [45]2 years ago

8 0

Answer:

$- 6k - 7 - (15 - k) \\ = - 6k - 7 - 15 + k \\ = - 5k - 22 \\ thank \: you$

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If f(x) = x2 – 2x + 3, then find f(-3).

Georgia [21]

Answer:

f(-3) = 18

Step-by-step explanation:

We need just substitute x with (-3) and calculate it.

f(-3) = (-3)² -2*(-3) + 3 = 9 + 6 +3 = 18

7 0

3 years ago

A botanist was measuring how tall her plant grew. After two weeks it had grown 12.55 inches. The second week alone it had grown

Step2247 [10]

Answer:10.10

Step-by-step explanation:

1o.10

4 0

3 years ago

If a polynomial function f(x) has roots -8, 1, and 6i, what must also be a root of f(x)?

Naddik [55]

Answer:

it must also have the root : - 6i

Step-by-step explanation:

If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.

This is because in order to render a polynomial with Real coefficients, the binomial factor (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:

$(x-(a+bi))*(x-(a-bi))=\\(x-a-bi)*(x-a+bi)=\\([x-a]-bi)*([x-a]+bi)=\\(x-a)^2-(bi)^2=\\(x-a)^2-b^2(-1)=\\(x-a)^2+b^2$

where the imaginary unit has disappeared, making the expression real.

So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)

Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.

5 0

3 years ago

The first three steps of completing the square to solve the quadratic equation x2 +4x-6=0

hodyreva [135]

Answer:

Step-by-step explanation:

1. Move the 6 to the other side: x^2 +4x =6

2. Square half the coefficient of the x term: (4/2)^2 = 4

3. Add this 4, and then subtract this 4, from x^2 + 4x:

x^2 +4x + 4 - 4 =6

4. Rewrite this perfect square as the square of a binomial:

(x + 2)^2 - 4 = 6

5. Add 4 to both sides: (x + 2)^2 = 10

6. Find the sqrt of both sides: x + 2 = √

8 0

3 years ago

Can anybody help me please

GREYUIT [131]

Question 7: Option 1: x = 33.5°

Question 8: Option 3: x = 14.0°

Step-by-step explanation:

Question 7:

In the given figure, the value of perpendicular and hypotenuse is given, so we have to use any trigonometric ratio to find the value of angle as the given triangle is a right-angled triangle

So,

Perpendicular = P = 32

Hypotenuse = H = 58

So,

$sin\ x = \frac{P}{H}\\sin\ x = \frac{32}{58}\\sin\ x = 0.5517\\x = sin^{-1} ( 0.5517)\\x =33.48$

Rounding off to nearest tenth

x = 33.5°

Question 8:

In the given figure, the value of Base and Perpendicular is given, we will use tangent trigonometric ratio to find the value of x

So,

Perpendicular = P = 5

Base = B = 20

So,

$tan\ x = \frac{P}{B}\\tan\ x = \frac{5}{20}\\tan\ x = 0.25\\x = tan^{-1} (0.25)\\x = 14.036$

Rounding off to nearest tenth

x = 14.0°

Keywords: Right-angled triangle, trigonometric ratios

Learn more about trigonometric ratios at:

#LearnwithBrainly

8 0

3 years ago