Answer:
The word "ARRANGE" can be arranged in
2!×2!
7!
=
4
5040
=1260 ways.
For the two R's do occur together, let us make a group of R's taking from "ARRANGE" and permute them.
Then the number of ways =
2!
6!
=360.
The number ways to arrange "ARRANGE", where two "R's" will not occur together is =1260−360=900.
Also in the same way, the number of ways where two "A's" are together is 360.
The number of ways where two "A's" and two "R's" are together is 5!=120.
The number of ways where neither two "A's" nor two "R's" are together is =1260−(360+360)+120=660.
Step-by-step explanation:
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Answer:
Big Chungus
Step-by-step explanation:
Doesn't really need any explanition.
The answer is -4 because you do (5x-1)=(x-17)
Answer:
I believe it is B
Step-by-step explanation:
plug in 4 where t is
Answer:
$1.20
Step-by-step explanation:
A dime is worth 10¢.
10¢ x 12 = 120¢
Since a dollar is 100¢, James would have a dollar and 20¢ left over. So, $1.20.
