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Advocard [28]
3 years ago
12

What family ruled russia for 300 years

Mathematics
2 answers:
Aleksandr [31]3 years ago
6 0
The Romanov family ruled for 300 years.
solong [7]3 years ago
4 0
The Romanov family was the family that ruled Russia for 300 years. Their last ruling was in the year 1918 by Nicholas the second.
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Calculate S58 for the arithmetic sequence {an}= {5/6n+1/3} If you could show me the steps that would be great. I keep following
Amanda [17]

Answer is 8671/6 which is the third choice

===================================

Work Shown:

Find the first term of the sequence by plugging in n = 1

a_n = (5/6)*n + 1/3

a_1 = (5/6)*1 + 1/3    replace n with 1

a_1 = 5/6 + 1/3

a_1 = 5/6 + 2/6

a_1 = 7/6

Repeat for n = 58 to get the 58th term

a_n = (5/6)*n + 1/3

a_58 = (5/6)*58 + 1/3    replace n with 58

a_58 = (5/6)*(58/1) + 1/3

a_58 = (5*58)/(6*1) + 1/3

a_58 = 290/6 + 1/3

a_58 = 145/3 + 1/3

a_58 = 146/3

Now we can use the s_n formula below with n = 58

s_n = (n/2)*(a_1 + a_n)

s_58 = (58/2)*(a_1 + a_58)    replace n with 58

s_58 = (58/2)*(7/6 + a_58)   replace a_1 with 7/6

s_58 = (58/2)*(7/6 + 146/3)   replace a_58 with 146/3

s_58 = (58/2)*(7/6 + 292/6)

s_58 = (58/2)*(299/6)

s_58 = (58*299)/(2*6)

s_58 = 17342/12

s_58 = 8671/6


5 0
3 years ago
3x + 3 − x + (−7) > 6 what is x
WARRIOR [948]

3x+3-x+(-7)>6

 combine like terms on left side

2x-4>6

add 4 to both sides 2x>10

x=10/2 = 5

x>5

6 0
3 years ago
5. Suppose that a particular candidate for public office is in fact favored by p = 48% of all registered voters. A polling organ
mart [117]

Answer:

Probability that the sample proportion will be greater than 0.5 is 0.8133.

Step-by-step explanation:

We are given that the a particular candidate for public office is in fact favored by p = 48% of all registered voters. A polling organization is about to take a simple random sample of voters and will use the sample proportion to estimate p.

Suppose that the polling organization takes a simple random sample of 500 voters.

<em>Let </em>\hat p<em> = sample proportion</em>

The z-score probability distribution for sample proportion is given by;

               Z = \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion

           p = population proportion = 48%

           n = sample of voters = 500

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample proportion will be greater than 0.5 is given by = P( \hat p > 0.50)

  P( \hat p > 0.50) = P( \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < \frac{0.50-0.48}{\sqrt{\frac{0.50(1-0.50)}{500} } } ) = P(Z < 0.89) = 0.8133

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.89 in the z table which has an area of 0.8133.</em>

Therefore, probability that the sample proportion will be greater than 0.50 is 0.8133.

6 0
3 years ago
What is 2.33 written as a mixed number in simplest form?
aleksandr82 [10.1K]
2.33.......ok, 2 is ur whole number....33 is ur fraction...the last digit is in the hundredths place....so put it over 100

ur mixed number is 2 33/100...and this does not reduce
8 0
3 years ago
Read 2 more answers
Can someone help with an explanation? This is finding Surface Area.​
Y_Kistochka [10]
The answer should be 95in^2

Explanation:

You’re essentially just finding the area of all the shapes on the triangle and adding them together.

Area of a triangle = 1/2•b•h
Area of a square = l•w or just s2

The area of the triangles given what we have in the diagram can be found with
1/2•5•7 = 17.5

There are 4 triangles so you multiply 17.5 by 4 which gives 70

The base of the triangle (the square) = 25

70+25=95
7 0
3 years ago
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