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qwelly [4]
3 years ago
10

What are the first 5 terms?

Mathematics
2 answers:
Mashutka [201]3 years ago
6 0

f(n) = f(n-1) + 1.75

f(1) = -5.25

f(2) = -5.25 + 1.75 = -3.5

f(3) = -3.5 + 1.75 = -1.75

f(4) = -1.75 + 1.75 = 0

f(5) = 0 + 1.75 = 1.75

Answer: -5.25  -3.5  -1.75  0  1.75

Anastaziya [24]3 years ago
4 0

<em>f(1) = - 5,25</em>

<em>f(n) = f(n-1) + 1,75</em>

<em>f(2) = f(2-1) + 1,75</em>

<em>= f(1) + 1,75</em>

<em>= - 5,25 + 1,75</em>

<em>= - 3,5</em>

<em>f(3) = - 3,5 + 1,75 = - 1,75</em>

<em>f(4) = - 1,75 + 1,75 = 0</em>

<em>f(5) = 0 + 1,75 = 1,75</em>

<em>The first five terms of the sequence :</em>

<em>- 5,25  -3,5  -1,75  0  1,75</em>

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Please help me on this
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Answer:

A =256 cm^2

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The perimeter of a square is 64 cm

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64 = 4s

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The value of n. 3n = (3^2)8
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Find the 9th term of the geometric sequence 5, -25, 125, ...
Mnenie [13.5K]

Answer:  1,953,125

This is one single value and it is just a bit under 2 million.

Or more accurately, it's a bit over 1.9 million.

===========================================================

Explanation:

  • a = 5 = first term
  • r = -5 = common ratio

Note that dividing any term by its previous term gets us the common ratio

  • r = term2/term1 = -25/5 = -5
  • r = term3/term2 = 125/(-5) = -5

The r value must stay the same the entire time, or else the sequence isn't geometric.

The nth term of any geometric sequence is a*(r)^(n-1). With the 'a' and 'r' values we found, we update that to 5(-5)^(n-1)

-----------------

To verify that is the correct nth term expression, plug in various values of n to compare it with the given sequence.

If we tried n = 2 for instance, then we find the 2nd term is

5(-5)^(n-1) = 5(-5)^(2-1) = -25

which matches what your teacher gave you. I'll let you verify the other terms.

-----------------

The last thing we need to do is plug in n = 9 and simplify

5(-5)^(n-1)

5(-5)^(9-1)

5(-5)^8

5(390625)

1,953,125  this is one single value (rather than 3 separate values)

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3 years ago
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