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3 years ago

8

If the height of a right triangle is 24 inches and the the area of the triangle is 120 square inches, what is the length of the

base?

1 answer:

Rus_ich [418]3 years ago

3 0

(120×2)/24 = 10inches

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3/4x-2/3=5/12. i need help

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2 years ago

A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$

In point c)

$\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\$

In point d)

using standard normal variate

$x=20.17\\\\ z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17$

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2 years ago

If the interest rate is 5% how long will it take you to double your money

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Answer:14.4 years

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3 years ago

A mass attached to a spring is pulled towards the floor then let go. Its height is recorded and

andreev551 [17]

First find the derivative,

$\dfrac{d}{dt}\Big(-10\cos(4t)\Big)=40\sin(4t)$ .

Then find the critical point,

$40\sin(4t)=0\implies t=40\mathrm{s}$ .

Hope this helps.

I am a little rusty here :(.

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2 years ago

Simplify the expression below. 14a8y3 − 7a4y5 + 28a12y2 7a4y

olchik [2.2K]

Answer:

$14a^{8}y^{3} - 7a^{4}y^{5} + 4a^{8} y$

Step-by-step explanation:

$14a^{8}y^{3} - 7a^{4}y^{5} + \frac{28a^{12}y^{2}}{7a^{4} y}$

$14a^{8}y^{3} - 7a^{4}y^{5} + 4a^{8} y$

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2 years ago