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lubasha [3.4K]
3 years ago
7

What is account? what are the purpose of account.​

Mathematics
2 answers:
kakasveta [241]3 years ago
5 0
To answer question i think?
kirza4 [7]3 years ago
3 0

Answer:

account is bascially when u make an account to use stuff like brainly

Step-by-step explanation:

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Helpp please thanksss
Brilliant_brown [7]

Answer:

The function show the value of the machinery after "t" years.

So After "4" years... Input "t" as 4 to get its value

f(t) = 12,500 - 1,600(4)

=$6,100

OPTION C IS LEGIT!!!

8 0
3 years ago
Plssss help (ZOOM IN TO SEE FULL PIC)
MA_775_DIABLO [31]

Answer:

d and e

Step-by-step explanation:

IV must have a pos x value and a negative y value

we can eliminate everything except d e & f

f is wrong bc it has a positive 3 value

5 0
3 years ago
Alfred made 20 goals in 3.5 minutes.what is alfreds unit rate per goal
Veseljchak [2.6K]
I belive the unit rate per goal is 5.7
5 0
3 years ago
What is the area of a rectangle that has side lengths of 3/4 yard and 5/6 yard
Ahat [919]

We are asked to find the area of the rectangle that has side lengths of 3/4 yard and 5/6 yard.

We know that area of rectangle is width times length.

To find the area of the given rectangle we will multiply both side lengths as:

\text{Area of rectangle}=\text{Width}\times \text{Length}

\text{Area of rectangle}=\frac{3}{4}\text{ yard}\times\frac{5}{6}\text{ yard}

\text{Area of rectangle}=\frac{3}{4}\times\frac{5}{6}\text{ yard}^2

\text{Area of rectangle}=\frac{1}{4}\times\frac{5}{2}\text{ yard}^2

\text{Area of rectangle}=\frac{1\times5}{4\times2}\text{ yard}^2

\text{Area of rectangle}=\frac{5}{8}\text{ yard}^2

Therefore, the area of the given rectangle would be \frac{5}{8} square yards.

5 0
3 years ago
part 3. Find the coordinates of the vertices of the triangle after a reflection across the y-axis and then across the line y= 2.
garik1379 [7]

Answer:

  c.  S'(3, 1), T'(1, -1), U'(0, 1)

Step-by-step explanation:

Reflection across the y-axis negates the x-coordinate, so is equivalent to the transformation ...

  (x, y) ⇒ (-x, y)

Reflection across the horizontal line y=c is equivalent to the transformation ...

  (x, y) ⇒ (x, 2c-y)

So, the combined reflections are equivalent to the transformation ...

  (x, y) ⇒ (-x, 4 -y)

Then we have ...

  S(-3, 3) ⇒ S'(-(-3), 4-3) = S'(3, 1)

  T(-1, 5) ⇒ T'(-(-1), 4-5) = T'(1, -1)

  U(0, 3) ⇒ U'(-(0), 4-3) = U'(0, 1) . . . . matches choice C

7 0
3 years ago
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