Ask question

Ask question

All categories

3 years ago

5

The ratio of small dogs to large dogs at the dog show is 423 if there are 56 dogs in the show how many are large dogs. please sh

ow work

2 answers:

Anarel [89]3 years ago

8 0

Ok if there is 423 dogs and 56 big dogs need to sub the dogs and you get
423-56=357 big dogs

SO there are 357 dig dogs

IceJOKER [234]3 years ago

5 0

i think the answer is 357

You might be interested in

David has four bags of apples and two bags of mangoes. The first four bags contain 6 apples each and the bags with mangoes conta

Neko [114]

Answer:

tal vez sea el fotosíntesis pero no creo jaja

Step-by-step explanation:

pero mañana va?

3 0

3 years ago

Read 2 more answers

Two students are reading a novel. Ashley reads 10 pages per day. Carly reads 8 pages per day, but she starts

natulia [17]

Answer:

On day 20, they should both be on page 200

Step-by-step explanation:

I set the 2 equations up:

10d=8d+40 and then subtracted 8d from both sides

2d=40 and then divided both sides by 2

d=20

I then took 20 and multiplied it by 10 for Ashley (200) and then multiplied it by 8 for Carly (160) and added 40 (200)

Hope this helps!

3 0

3 years ago

Thomas buys 6 souvenirs for his friends and family. Each gift takes up 1/15 of his suitcase. If he has two suitcases, how much r

Gala2k [10]

Answer:

<u>Thomas still has 1 3/5 suitcases available for his own belongings.</u>

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Number of souvenirs bought by Thomas = 6

Space that each souvenir takes of Thomas suitcase = 1/15

Number of Thomas suitcases = 2

2. How much room is left for his own belongings in his suitcases?

Let's find out how much space the souvenirs take:

Number of souvenirs * Space that each souvenir takes

6 * 1/15 = 6/15 = 2/5 (Dividing by 3 the numerator and the denominator)

The souvenirs take 2/5 of one suitcase.

Now, we can calculate the room that is left for Thomas' belongings.

2 Suitcases - 2/5 for the souvenirs

2 - 2/5 = 10/5 - 2/5 = 8/5 = 1 3/5

<u>Thomas still has 1 3/5 suitcases available for his own belongings.</u>

6 0

3 years ago

What is the answer to this ? PLEASE HELP I HAVE 3 minutes

inn [45]

Answer:

(2, 4)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

<u>Algebra I</u>

Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = 2x

x = -y + 6

<u>Step 2: Solve for </u><em><u>y</u></em>

<em>Substitution</em>

Substitute in <em>x</em>: y = 2(-y + 6)
Distribute 2: y = -2y + 12
Isolate <em>y</em> terms: 3y = 12
Isolate <em>y</em>: y = 4

<u>Step 3: Solve for </u><em><u>x</u></em>

Define equation: x = -y + 6
Substitute in <em>y</em>: x = -4 + 6
Add: x = 2

3 0

3 years ago

A person invests $4000 at 2% interest compounded annually for 4 years and then invests the balance (the $4000 plus the interest

faltersainse [42]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4000\\
r=rate\to 2\%\to \frac{2}{100}\to &0.02\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &4
\end{cases}
\\\\\\
A=4000\left(1+\frac{0.02}{1}\right)^{1\cdot 4}\implies A=4000(1.02)^4\implies A\approx 4329.73$

then she turns around and grabs those 4329.73 and put them in an account getting 8% APR I assume, so is annual compounding, for 7 years.

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4329.73\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &7
\end{cases}
\\\\\\
A=4329.73\left(1+\frac{0.08}{1}\right)^{1\cdot 7}\implies A=4329.73(1.08)^7\\\\\\ A\approx 7420.396$

add both amounts, and that's her investment for the 11 years.

7 0

3 years ago