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givi [52]
3 years ago
11

How is multiplication using partial products different from multiplication using regrouping?

Mathematics
2 answers:
klio [65]3 years ago
5 0
Partial products is breaking down every number in multiplication and adding them. Regrouping is grouping number them adding them.They are alike because they both involve breaking down the numbers and adding them.  They are different because one is taking all the numbers broken down, while the other is just a couple of the number.
shtirl [24]3 years ago
3 0
Partial products are basically when you break down every number and add them.
I'm sure you know how to regroup.
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He variable y is directly proportional to the variable x . If y = 10 when x = 6, what is the value of y when x = 15?
Delicious77 [7]

Answer:

B. 25

Step-by-step explanation:

10+6=16

if it is proportional, then it would be 25 to get 15.

4 0
3 years ago
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The distance between Henry's house and his school is 648 feet. How many yards are equivalent to 648 feet?
vlabodo [156]

Answer:

216 yards

Step-by-step explanation:

There are 3 feet in a yard, so the number of yards is equal to the number of feet divided by 3.

648/3 = 216

5 0
3 years ago
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The prism has a surface area of 1312 mm2.
777dan777 [17]
So each dimention is 32 by 8 by 10
so the surface area=2 times(8 times 10)+(2 times (32 times 10))+(2 times (8 times 32))=2 times 80+2 times 320+2 times 256=1312

if halved
just divide each by 2
(2 times 4 times 5)+(2 times 16 times 5)+(2 times 4 times 16)=(2 times 20)+(2 times 80)+(2 times 64)=40+160+128=328
the new surface area is 328 mm^2
4 0
3 years ago
1.) Determine the type of solutions for the function (Picture 1)
NNADVOKAT [17]

Answer:

1) 2 nonreal complex roots

2) 1 Real Solution

3) 16

4) Reflected, narrower by a factor of 2/5, slides right 4 units and slides up 6 (units)

Step-by-step explanation:

1) The graph does not intercept the x-axis, therefore, there are no real solutions at the point y = 0

We get;

y = a·x² + b·x + c

At y = 6, x = -2

Therefore;

6 = a·(-2)² - 2·b + c = 4·a - 2·b + c

6 = 4·a - 2·b + c...(1)

At y = 8, x = 0

8 = a·(0)² + b·0 + c

∴ c = 8...(2)

Similarly, we have;

At y = 8, x = -4

8 = a·(-4)² - 4·b + c = 16·a - 4·b + 8

16·a - 4·b = 0

∴ b = 16·a/4 = 4·a

b = 4·a...(3)

From equation (1), (2) and (3), we have;

6 = 4·a - 2·b + c

∴ 6 = b - 2·b + 8 = -b + 8

6 - 8 = -b

∴ -b = -2

b = 2

b = 4·a

∴ a = b/4 = 2/4 = 1/2

The equation is therefor;

y = (1/2)·x² + 2·x + 8

Solving we get;

x = (-2 ± √(2² - 4 × (1/2) × 8))/(2 × (1/2))

x =( -2 ± √(-12))/1 = -2 ± √(-12)

Therefore, we have;

2 nonreal complex roots

2) Give that the graph of the function touches the x-axis once, we have;

1 Real Solution

3) The given function is f(x) = 2·x² + 8·x + 6

The general form of the quadratic function is f(x) = a·x² + b·x + c

Comparing, we have;

a = 2, b = 8, c = 6

The discriminant of the function, D = b² - 4·a·c, therefore, for the function, we have;

D = 8² - 4 × 2 × 6 = 16

The discriminant of the function, D = 16

4.) The given function is g(x) = (-2/5)·(x - 4)² + 6

The parent function of a quadratic equation is y = x²

A vertical translation is given by the following equation;

y = f(x) + b

A horizontal to the right by 'a' translation is given by an equation of the form; y = f(x - a)

A vertical reflection is given by an equation of the form; y = -f(x) = -x²

A narrowing is given by an equation of the form; y = b·f(x), where b < 1

Therefore, the transformations of g(x) from the parent function are;

g(x) is a reflection of the parent function, with the graph of g(x) being narrower by 2/5 than the graph of the parent function. The graph of g(x) is shifted right by 4 units and is then slides up by 6 units.

7 0
2 years ago
The volume of 2 spheres have a ratio of 27:125. what is the ratio of their radii
Citrus2011 [14]
The volume is scale factor³
Take the square root of the volume ratio

\sqrt{ \frac{27}{125} } which is 
\frac{ \sqrt{27} }{ \sqrt{125} }

\frac{3}{5}

The ratio of their radii is 3 : 5
3 0
3 years ago
Read 2 more answers
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