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givi [52]
4 years ago
11

How is multiplication using partial products different from multiplication using regrouping?

Mathematics
2 answers:
klio [65]4 years ago
5 0
Partial products is breaking down every number in multiplication and adding them. Regrouping is grouping number them adding them.They are alike because they both involve breaking down the numbers and adding them.  They are different because one is taking all the numbers broken down, while the other is just a couple of the number.
shtirl [24]4 years ago
3 0
Partial products are basically when you break down every number and add them.
I'm sure you know how to regroup.
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Step-by-step explanation:

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Which expression is equivalent to (73)5 • 74 ?
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The correct answer is D. 73 • 5 • 74

Explanation:

In mathematics, multiplication can be represented by using the symbol × or the symbol ·. Moreover, multiplication can be also represented just by leaving the numbers or values side by side without any symbol. For example, the expression 5x + y implies 5 should be multiplied by x. In this context, the expression (73)5 • 74  indicates 5 should be multiplied by 74, and the result of this should be multiplied by 73 as the lack of symbol indicates multiplication. Therefore, this is equivalent to 73 • 5 • 74.

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3 years ago
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5 0
3 years ago
Read 2 more answers
A streamer goes downstream from point A to B in 9hrs .from B to A ,upstream it takes 10h .if the speed is 1km/hr , what will be
MA_775_DIABLO [31]

Answer:

Speed\ of\ streamer\ in\ still\ water=19\ km/hr\\\\Distance=180\ km

Step-by-step explanation:

Let\ speed\ of\ steamer\ in\ still\ water=x\ km/hr\\\\Let\ distance\ between\ A\ and\ B=d\ km

Downstream:

Speed of stream=1\ km/hr\\\\Downstream\ speed=speed\ of\ steamer+speed\ of\ stream\\\\Downstream\ speed=x+1\\\\Time\ Taken=9\ hrs\\\\Distance=d\\\\Distance=speed\times time\\\\d=(x+1)\times 9\\\\d=9x+9\ ..................................................eq(1)

Upstream:

Speed of stream=1\ km/hr\\\\Upstream\ speed=speed\ of\ steamer-speed\ of\ stream\\\\Downstream\ speed=x-1\\\\Time\ Taken=10\ hrs\\\\Distance=d\\\\Distance=speed\times time\\\\d=(x-1)\times 9\\\\d=10x-10\ ..................................................eq(2)

From\ eq(1)\ and\ eq(2)\\\\10x-10=9x+9\\\\10x-9x=10+9\\\\x=19\\\\from\ equation\ 2\\\\d=10x-10\\\\d=10\times 19-10=190-10\\\\d=180

Speed\ of\ streamer\ in\ still\ water=19\ km/hr\\\\Distance=180\ km

3 0
3 years ago
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