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Nikolay [14]
2 years ago
5

Modal 9 10 11 14 19 22 27 29 21 18 11 6

Mathematics
1 answer:
Marat540 [252]2 years ago
7 0

Answer:

modal is 11. it's the correct answer

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Mr. Waugh paid $42.00 for 12 gallons of gasoline. Ms. Peters paid $31.50 for 9 gallons of gasoline. What was theprice per gallon
dmitriy555 [2]

Answer:

$3.50 per pound

Step-by-step explanation:

Divide 42  by 12 or 31.5 by 9 and you get 3.5. In money, that is $3.50

4 0
3 years ago
Read 2 more answers
Given that AXB is complementary to both CYD and FZE, and mAXB = 36°, what is mCYD + mFZE?
anyanavicka [17]
Complementary angles always equal 90°
So here is how to find what mCYD + mFZE equal 
mCYD + mFZE + mAXB
mCYD + mFZE + 36° = 90°
Subtract 
mCYD + mFZE = 54°
7 0
3 years ago
In a list of households, own homes and do not own homes. Five households are randomly selected from these households. Find the p
hichkok12 [17]

Answer:

The probability of success for this case would be:

p =\frac{9}{15}= 0.6 representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=15, p=0.6)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And we want this probability:

P(X=3)

And uing the probability mass function we got:

P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165

Step-by-step explanation:

Adduming the following info: In a list of 15 households, 9 own homes and 6 do not own homes. Five households are randomly selected from these 15 households. Find the probability that the number of households in these 5 own homes is exactly 3.

Round your answer to four decimal places

P (exactly 3)=

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Solution to the problem

The probability of success for this case would be:

p =\frac{9}{15}= 0.6 representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=15, p=0.6)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And we want this probability:

P(X=3)

And uing the probability mass function we got:

P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165

4 0
2 years ago
Omar grouped the terms and factored the GCF out of the groups of the polynomial 3x3 – 15x2 – 4x + 20. His work is shown.
Phoenix [80]

Answer:

2nd option

Step-by-step explanation:

Given

3x³ - 15x² - 4x + 20

step 1 ( group the first/second and third/fourth terms )

(3x³ - 15x² ) + (- 4x + 20)

step  2 ( factor each group )

3x² (x - 5) - 4(x - 5) ← note factor of - 4 ( not + 4 )

step 3 ( factor out (x - 5) from each term )

(x - 5)(3x² - 4)

4 0
2 years ago
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terry,sasha and harry each chose a number. terry's number is ten times as much as sasha's. harry's number is 1 over 10 of sasha'
PilotLPTM [1.2K]
Harry's number is 0.04, and Terry's number is 4.

Hope this helps!
8 0
2 years ago
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