Question

A spinner is divided into sections of equal size, some of which are red, some are blue, and the remaining are green. The probability of the arrow landing on a section colored red is 25%. The probability of the arrow landing on a section colored blue is 10%. What is the probability of the arrow landing on a section colored green?

Answer 1

Answer:

The probability of the arrow landing on a section colored green is 65%.      

Step-by-step explanation:

Given : A spinner is divided into sections of equal size, some of which are red, some are blue, and the remaining are green.

The probability of the arrow landing on a section colored red is 25%.

The probability of the arrow landing on a section colored blue is 10%.

To find : The probability of the arrow landing on a section colored green

Solution :

→ The probability of the arrow landing on a section colored red is 25%.

i.e, $P(R)=25\%=\frac{25}{100}=0.25$

→ The probability of the arrow landing on a section colored blue is 10%.

i.e, $P(B)=10\%=\frac{10}{100}=0.10$

→ Probability of the spinner is P(R)+P(B)+P(G)=1

To find the probability of section green colored, substitute the value

$P(R)+P(B)+P(G)=1$

$0.25+0.10+P(G)=1$

$0.35+P(G)=1$

$P(G)=1-0.35$

$P(G)=0.65$

Convert into percentage,

$0.65=\frac{65}{100}\times 100=65\%$

Therefore,The probability of the arrow landing on a section colored green is 65%.

Answer 2

I believe it is 65% because you add 25% and 10% together then subtract from 100, because percent means per 100. So, sorry if I am wrong.