3 years ago

How many solutions are in the equation 3x^2+4x-7=0?

1 answer:

kramer3 years ago

4 0

Hello :
the equation 3x^2+4x-7=0 has 2 solutions because : ac < 0
a = 3 b=4 c= -7
Δ = b²-4ac....... b² ≥ 0 and -4ac > 0 ..... (ac < 0 )
coclusion : Δ>0.....(2 solutions)

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