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mars1129 [50]
4 years ago
8

What polynomial should be subtracted from the polynomial y^2–5y+1 to get the difference equal to 4y^2-y+7

Mathematics
1 answer:
kolezko [41]4 years ago
3 0
Y^2-5y+1- a= 4y^2-y+7

a=y^2- 4y^2-5y+y+1-7

a= -3 y^2 - 4y - 6    this is the polynomial
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How to break down 4/5 + 13/15 = 1 2/3
nalin [4]

Answer:

Step-by-step explanation:

The left hand side of the equation contains proper fractions while the right hand side of the equation contains mixed fraction. The mixed fraction can be changed to improper fraction. 1 2/3 becomes 5/3

To breakdown the left hand side of the equation, we would take lowest common factor of 5 and 15. It is 15

Considering 4/5, if 15 divides 5,the result is 3. Multiplying 3 by 4 gives 12. So it becomes

12/15

Considering 13/15, if 15 divides 15,the result is 1, Multiplying 1 by 13 gives 13. So it becomes

13/15

The equation becomes

(12 + 13)/15 = 5/3

25/15 = 5/3

Simplifying 25/15 to its lowest terms, it becomes 5/3 so

5/3 = 5/3

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3 years ago
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The correct answer is x=1/2
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Pls help me and can you give tips on exponents??!
Marina CMI [18]

Answer:

Basically, exponents represent the number of times you multiply that number by itself. For example, 3² = 9, because you multiply 3 times 3.

Step-by-step explanation:

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3 years ago
A student’s first step to solving the equation 5(x – 2) = 10 was to simplify it to 5x – 2 = 10. Did the student make a mistake?
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NEED THE ANSWER ASAP, PLEASE HELP!! What are the coordinates of the focus of the parabola?
qwelly [4]

Answer:

Vertex is (-8, 4)  not one of the answers offered!

Step-by-step explanation:

Factor -1/8 out of the first two terms. Leave a space inside parentheses in which to add a number.

y=-\frac{1}{8}(x^2 + 16x + \text{-----})-4

Complete the square by squaring half the coefficient of <em>x </em>and adding it in the space.

(\frac{16}{2})^2=64

Add 64 in the space you made, then compensate for that at the end of the expression by <u>subtracting</u>  -\frac{1}{8}(64)=-8

y=-\frac{1}{8}(x^2+16x+64)-4+8\\y=-\frac{1}{8}(x+8)^2+4

The x-coordinate of the vertex is the <u>opposite</u> of +8, the number inside the parentheses.  The y-coordinate of the vertex is the number at the end of the expression.

V(-8, 4)

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