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3 years ago

8

What polynomial should be subtracted from the polynomial y^2–5y+1 to get the difference equal to 4y^2-y+7

1 answer:

kolezko [41]3 years ago

3 0

Y^2-5y+1- a= 4y^2-y+7

a=y^2- 4y^2-5y+y+1-7

a= -3 y^2 - 4y - 6 this is the polynomial

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Francis went to the sporting goods store and spent $75.15 on 6 items.

MArishka [77]

Answer:

$6.03

Step-by-step explanation:

The question is asking us how much each pair of socks cost. With the information we are given, we know that there are 5 pairs and that they all cost the same amount. If the total were just the 5 socks, we could easily divide the total by 5 to get the price of each pair but that's not the case. The soccer ball is included in the final cost. To overcome this, we just have to subtract the soccer ball's cost ($45) from the total.

So we subtract $45 from $75.15, giving us $30.15, the total amount of all the socks. However we need to find out how much each pair costs and there are 5 of them, so we divide 30.15 by 5. This gives us the answer, $6.03.

Each pair of socks cost $6.03.

Simpler Explanation:

$75.15 - $45 = $30.15
$30.15 / 5 = $6.03

The answer is $6.03

5 0

2 years ago

PLEASEEEEE HELPPPP MEEEEEEE BRAINLIEST TO THE FIRST ANSWER AND 30 POINTS

icang [17]

Answer:

CD ≠ EF

Step-by-step explanation:

Using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = C(- 2, 5) and (x₂, y₂ ) = D(- 1, 1)

CD = $\sqrt{(-1+2)^2+(1-5)^2}$

= $\sqrt{1^2+(-4)^2}$

= $\sqrt{1+16}$ = $\sqrt{17}$

Repeat using (x₁, y₁ ) = E(- 4, - 3) and (x₂, y₂ ) = F(- 1, - 1)

EF = $\sqrt{(- 1+4)^2+(-1+3)^2}$

= $\sqrt{3^2+2^2}$

= $\sqrt{9+4}$ = $\sqrt{13}$

Since $\sqrt{17}$ ≈ $\sqrt{13}$ , then CD and EF are not congruent

6 0

2 years ago

PLEASE HELP ME ASAP ILL GIVE 100 POINTS

Airida [17]

Answer:

8(+4)

Step-by-step explanation:

6 0

2 years ago

SOS if anyone could help that would be appreciated!!!❤️

Anastaziya [24]

Answer:

See below

Step-by-step explanation:

$2e)15-4x=10x+45$

Solve:

$15-4x=10x+45\\-4x-10x=45-15\\-14x=30\\ \boxed {x=-\dfrac{15}{7}}$ $3(x+1)=21$

Check:

$15-4 \left(-\dfrac{15}{7} \right)=10\left(-\dfrac{15}{7} \right)+45$

$15+\dfrac{60}{7} \right)=-\dfrac{150}{7} +45$

$\dfrac{210}{7} =30$

$30=30$

$3a) 3(x+1)=21$

Solve:

$3(x+1)=21\\3x+3=21\\3x=18\\x=6$

$3b) 2+3(x+1)=6x$

$2+3x+3=6x\\5=3x\\$

$x=\dfrac{5}{3}$

$3c) -2(2x-3)=-2$

Solve:

$-2(2x-3)=-2\\-4x+6=-2\\-4x=-8\\x=2$

3 0

2 years ago

Evaluate 32 divided by 2^3 + 12

matrenka [14]

Answer: 8/5

Step-by-step explanation:

2^3 = 2*2*2 = 8

Therefore, you are evaluating 32/(8+12)

= 32/20

= 8/5

4 0

1 year ago

Read 2 more answers