Answer:
<h2>The value of a is
.</h2>
Step-by-step explanation:
At the time of purchase, the value of the antique is $200.
After one year the value will increase 10%.
Hence, after one year, the value of the antique will be 
= 220.
Similarly, after two year, the value will be 
.
Thus, 222 years after purchase, the value of the antique will be 
.
We can solve this by setting up a proportion:
12 seeing the play/ 72 students = 210 seeing the play/ x students
We can cross multiply to solve for x:
(12)x=(72)(210)
12x=15,120
x=1,260 students who attend the school
the probability of selecting a blue crayon for the bag is 16.7% while estimate probability of selecting a red crayon is 20% and the most likely crayon to be selected is brown crayon and also the possibility of getting a real possibility of the number of crayons in the bag is 60
No.
Since w = 8, you must replace the variable with the number associated to it.
So, it would be 5 + 8 = 58
5 + 8 is not equal to 58, it is equal to 13.
If you wanted to find out what w was, simply subtract 5 on both sides.
w = 58 - 5
You do the implcit differentation, then solve for y' and check where this is defined.
In your case: Differentiate implicitly: 2xy + x²y' - y² - x*2yy' = 0
Solve for y': y'(x²-2xy) +2xy - y² = 0
y' = (2xy-y²) / (x²-2xy)
Check where defined: y' is not defined if the denominator becomes zero, i.e.
x² - 2xy = 0 x(x - 2y) = 0
This has formal solutions x=0 and y=x/2. Now we check whether these values are possible for the initially given definition of y:
0^2*y - 0*y^2 =? 4 0 =? 4
This is impossible, hence the function is not defined for 0, and we can disregard this.
x^2*(x/2) - x(x/2)^2 =? 4 x^3/2 - x^3/4 = 4 x^3/4 = 4 x^3=16 x^3 = 16 x = cubicroot(16)
This is a possible value for y, so we have a point where y is defined, but not y'.
The solution to all of it is hence D - { cubicroot(16) }, where D is the domain of y (which nobody has asked for in this example :-).
(Actually, the check whether 0 is in D is superfluous: If you write as solution D - { 0, cubicroot(16) }, this is also correct - only it so happens that 0 is not in D, so the set difference cannot take it out of there ...).
If someone asks for that D, you have to solve the definition for y and find that domain - I don't know of any [general] way to find the domain without solving for the explicit function).
