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Slav-nsk [51]
1 year ago
9

twice the sum of the number and negative seven is eight. Find the number. Round your answer to the nearest integer, if necessary

Mathematics
1 answer:
Ugo [173]1 year ago
3 0

The number that twice the sum of it and negative seven is eight is 11.

<h3>How to find the number ?</h3>

Twice the sum of the number and negative seven is eight. The number can be found as follows:

let

the number  = x

According to the word expression, twice the value of  the addition of x and minus seven is equals to 8. Hence, we will find the value of x in the equation formed from the words expression.

The variable x is the required number.

Therefore,

2(x + (-7)) = 8

2(x - 7) = 8

open the brackets

2(x - 7) = 8

2x  - 14 = 8

add 14 to both sides of the equation

2x  - 14 = 8

2x  - 14 + 14 = 8 + 14

2x = 22

divide both sides by 2

x = 22 / 2

x = 11

learn more on numbers here: brainly.com/question/11234992

#SPJ1

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Consider two boxes, one containing one black and one white marble, the other, two black and one white marble. A box is selected
valina [46]

Answer:

\frac{7}{12}

Step-by-step explanation:

Probability refers to chance of happening of some event.

Conditional probability is the probability of an event A, given that another event B has already occurred.

B_1,B_2 denote the two boxes.

In box B_1:

No. of black balls = 1

No. of white balls = 1

In box B_2:

No. of black balls = 2

No. of white balls = 1

Let B, W denote black and white marble.

So, probability that either of the boxes B_1,B_2 is chosen is \frac{1}{2}

Probability that a black ball is chosen from box B_1 = \frac{1}{2}

Probability that a black ball is chosen from box B_2=\frac{2}{3}

To find:probability that the marble is black

Solution:

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6 0
3 years ago
Write the standard form equation of the ellipse shown in the graph, and identify the foci.
vlada-n [284]

Answer option A

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Center of ellipse = (-2,-3)

Vertices are (-2,3)  and (-2,-9)

Co vertices are (-6,-3) and (2,-3)

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The distance between center and covertices = 4 , so b= 4

The general equation of vertical ellipse is

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we know center is (-2,-3)

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The standard equation  becomes

\frac{(x+2)^2}{4^2} + \frac{(y+3)^2}{6^2}=1

\frac{(x+2)^2}{16} + \frac{(y+3)^2}{36}=1

Foci  are (h,k+c)  and (h,k-c)

c=\sqrt{a^2-b^2}

Plug in the a=6  and b=4

c=\sqrt{6^2-4^2}

 c=\sqrt{20}

  c=2\sqrt{5}, we know h=-2  and k=-3

Foci  are   (-2,-3+2\sqrt{5})  and  (-2,-3-2\sqrt{5})

Option A is correct

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