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Diano4ka-milaya [45]
3 years ago
9

Need help , use pics ^

Mathematics
1 answer:
Rashid [163]3 years ago
8 0

Answer:

Step-by-step explanation:

Are there any other pictures of the actual problem?

This is proabbaly a transformation problem

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A survey of an urban university (population of 25,450) showed that 870 of 1,100 students sampled supported a fee increase to fun
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Answer:

95% confidence interval for the proportion of students supporting the fee increase is [0.767, 0.815]. Option C

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The confidence interval for a proportion is given as [p +/- margin of error (E)]

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n is sample size = 1,100

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Upper limit of proportion = p + E = 0.791 + 0.024 = 0.815

95% confidence interval for the proportion of students supporting the fee increase is between a lower limit of 0.767 and an upper limit of 0.815.

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