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devlian [24]
3 years ago
11

What is the are of the figure below radius 6in 6in 6in 6in

Mathematics
1 answer:
Verdich [7]3 years ago
3 0

Answer:

ok

Step-by-step explanation:

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Omials<br> GCF of 96x5 and 64x2?
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32
the greatest common factor of 480 and 128 is 32
480 / 32 = 15
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3 0
3 years ago
X = ? y = ? 16 45 degrees
mezya [45]

Let's put more details in the figure to better understand the problem:

Let's first recall the three main trigonometric functions:

\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}\text{ Tangent }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Adjacent Side}}

For x, we will be using the Cosine Function:

\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}Cosine(45^{\circ})\text{ = }\frac{\text{ x}}{\text{ 1}6}(16)Cosine(45^{\circ})\text{ =  x}(16)(\frac{1}{\sqrt[]{2}})\text{ = x}\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}\text{ 8}\sqrt[]{2}\text{ = x}

Therefore, x = 8√2.

For y, we will be using the Sine Function.

\text{  Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}\text{ Sine }(45^{\circ})\text{ = }\frac{\text{ y}}{\text{ 1}6}\text{ (16)Sine }(45^{\circ})\text{ =  y}\text{ (16)(}\frac{1}{\sqrt[]{2}})\text{ = y}\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}\text{ 8}\sqrt[]{2}\text{ = y}

Therefore, y = 8√2.

5 0
1 year ago
(30 Points) Simplify Each Expression And Show Steps/Work
Nutka1998 [239]

1) (2i-4)-(6i+9) = 2i-4-6i-9 = -4i-13

2) (-3+8i)+(3-8i) = -3+8i+3-8i = 0+0i = 0

8 0
3 years ago
I need help on this one
mel-nik [20]

Answer: 4/9

Step-by-step explanation:

apply product rule to 2/3 2^2  /   3^2

7 0
3 years ago
Find the endpoint give one endpoint and the midpoint. Please put your
vitfil [10]

Answer:

Step-by-step explanation: -1, 16

3 0
3 years ago
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