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sattari [20]
3 years ago
15

Store A uses the newsvendor model to manage its inventory. Demand for its product is normally distributed with a mean of 500 and

a standard deviation of 300. Store A purchases the product for $10 each unit and sells each for $25. Inventory is salvaged for $5. What is its maximum profit? $5000 $12,500 $7500 $8000
Business
1 answer:
Llana [10]3 years ago
4 0

Answer:

maximum profit = $7500

so correct option is c  $7500

Explanation:

given data

mean = 500

standard deviation = 300

cost = $10

price = $25

Inventory  salvaged = $5

to find out

What is its maximum profit

solution

we get here maximum profit that is express as

maximum profit = mean × ( price - cost )   ..................................1

put here value in equation 1 we get maximum profit

maximum profit = mean × ( price - cost )

maximum profit = 500 × ( $25 - $10 )

maximum profit = 500 × $15

maximum profit = $7500

so correct option is c  $7500

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150/15= 10

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8 0
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In this case,  Jimmy should include word of Encouragement for  potential customers in the description section of his text ads

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5 0
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Answer:

Correct option is (5)

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5 0
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7 0
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