I think that there are 4 termms if we condider onlu plus and minus as operators.
1. A, It goes past the 4, but the circle is not shaded because the answer cannot be 4
2. C. It goes below the 11 and is shaded because it can be equal to 11
3. D. It is less than 13 and cannot equal thirteen, hence the non shaded circle
4. B. I goes past the -2 and has the circle shaded because it can be equal to the -2
Answer:
7, -1
Step-by-step explanation:
x^2 - 6x + 7 = 0
(x - 7)(x + 1) = 0
==> x = 7, x = -1
We're finding the function of (p+3), which means wherever there's an x, we're replacing it with (p+3).
2 (p+3)^2 + 3 (p+3) + 6
Foil out (p+3)^2.
2 (p^2 + 6p + 9) + 3 (p+3) + 6
Distribute.
2p^2 + 12p + 18 + 3p + 9 + 6
Add like terms.
g (p+3) = 2p^2 + 15p + 33
