Question

a falling stone is at a certain instant 230 feet above the ground. 3 seconds later it is only 14 feet above. From what height was it dropped?

Answer 1

The falling stone is a certain instant 230 feet above the ground. 3 seconds later it is only 14 feet above. The height that it was dropped is 32 feet. The equation for the answer is; 

16t2+h0=230 −16(t+3)2+h0=14

Answer 2

A falling object has the following height function due to acceleration of gravity (32 ft/s^2) h(t)=−16t2+v0t+h0
since object was dropped assume initial velocity of 0 plug in 2 given points to obtain system of 2 equations solve for t and initial height −16t2+h0=230 −16(t+3)2+h0=14